Support:
10% of 20 < 20% of 100 [2 < 20]
Refute:
10% of 100 > 20% of 20 [10 > 4]
Question:
Two rectangular picture frames have the same area of 45 square inches but have different side lengths. Frame A has a length of 6 3/4 inches, and Frame B has a length of 7 1/2 inches.
Answer:
1. the longer frame (B) has the shorter width
2. the shorter width is 6 3/7 inches, area divided by length
Step-by-step explanation:
The relation between area, length, and width is ...
A = LW
Then the width is ...
W = A/L . . . . . inversely proportional to length
1. Since length and width are inversely proportional (when area is constant), the shorter width will be associated with the longer length. Frame B will have the shorter width.__
2. The width of frame B is ...
W = A/L = (45 in²)/(7 in) = 45/7 in = 6 3/7 in
-Alan Becker
There is a strong, positive association
Age of tom=t
age of john=j
age of andy=a
t<a
if j is not older than t, then he is less than or equal to t so
j ≤ t
but there is an oldest so therefor we assume that j < t
t < a
j < t
subsitute
j<t<a
andy is oldest
tom is second
john is youngest
Answer:
Step-by-step explanation:
Corresponding parts of congruent triangles are congruent.
So, XY = AB
3a - 3.9 = 1.7a - 1.3
3a = 1.7a - 1.3 + 3.9
3a = 1.7a + 2.6
3a -1.7a = 2.6
1.3a = 2.6
a = 2.6/1.3
a = 2
ΔABC ≅ ΔXYZ
First two letter
AB = XY
Second and third letters
BC = YZ
Third and first letter
CA = ZX
