540 people can ride the wild river in 1 hour if all of the rafts are used and each raft is full
<u>Solution:</u>
Given, There are 15 rafts available for people to use on the adventure river ride.
Each raft holds 12 people.
Then, total people capacity over all rafts = 15 x 12 = 180 people.
The park runs this ride 3 times each hour.
We have to find how many people can ride the wild river in 1 hour if all of the rafts are used and each raft is full?
Then, <em>total people count who take ride = number of rides x number of people per ride
</em>
= 3 x 180 = 540
Hence, 540 people can take ride in 1 hour.
Answer:
22.86% probability that the persons IQ is between 110 and 130
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
If one person is randomly selected what is the probability that the persons IQ is between 110 and 130
This is the pvalue of Z when X = 130 subtracted by the pvalue of Z when X = 110.
X = 130
has a pvalue of 0.9772
X = 110
has a pvalue of 0.7486
0.9772 - 0.7486 = 0.2286
22.86% probability that the persons IQ is between 110 and 130
The sides of the box are 12in by 12in by 30in.
The interior diagonal =[12^2+12^2+30^2]0.5
=[144+144+900]^0.5
=1188^0.5
The final answer is 34.47in.
My deepest apology if this is not what you meant.
= 34.47in.
The greatest common factor will be (x² – xy + y²).
<h3>Greatest common factor</h3>
This is a value or expression that can divide the given expressions without leaving a remainder.
Given the following expressions
x^3+^3 and x^2 - xy + y^2
Expand x^3+y^3
x^3+y^3 =(x + y)(x² – xy + y²).
Since (x² – xy + y²) is common to both expression, hence the greatest common factor will be (x² – xy + y²).
Learn more on GCF here: brainly.com/question/902408
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