105% =$34.02
100% (cost without sales tax) = 34.02/1.05 =$32.40
Answer :
no. of days used to repair 1250m of road = 5
no. of days used to repair 1m of road = 5/1250
no. of days used to repair 8000m of road (8*1000m ) = 5/1250*8000= 32 days
Answer:
n squared + 3n + 1
Step-by-step explanation:
5,11,19,29
Firstly look at the difference between each number. The first difference is 6 then 8 then 10 etc. After that you look at your created sequence - 6,8,10 etc. The difference is 2 each time. Then applying rules, you have to do the constant difference divided by 2 to get a coefficient of n squared. So in this case it's n squared because 2/2 = 1 so you don't have to place a 1 in front of the n squared. After you create a sequence from the n squared. That would be 1,4,9 etc. Then you need to see how to get from the sequence: 1,4,9 etc to your original sequence: 5,11,19 etc. So if you calculate it you will get 4,7,10 because firstly 5-1 = 4 then 11-4 = 7 etc. The sequence 4,7,10 is a linear sequence so the constant difference is 3 each time. So to get a nth term of a linear sequence you will start off as 3n then you will substitute 1 then 2 then 3 into the 3n. Therefore that would be 3,6 etc. So if you take the first substituted term, that would be 3 as said before then you will have to see how to get from the 3 to 4 so that is just adding 1. So the nth term of this linear sequence is 3n + 1. Check if it works at the end. So the overall nth term of the quadratic sequence is n squared as said before + 3n + 1.
Answer: (C)
Step-by-step explanation:
Looking at the diagram the area occurring continuously over a period of time is the constant point which ranges from -4 to -2 making the answer C
Answer:
First option 
is the correct answer.
Step-by-step explanation:
Let us consider each part, we have number 6 inside all the roots.
First we have to find cube root of 6.
![\sqrt[3]{6} =6^\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B6%7D%20%3D6%5E%5Cfrac%7B1%7D%7B3%7D)
Now we have to find square root of this value.
So, first option is the correct answer.
