Given cos 0 = 4V2/7, find sin 0.<br> sin 0 =<br> V[?]/?

There are 8 2/3 pounds of walnuts in a container which will be divided equally into containers that hold 1 1/5 pounds this would

igomit [66]

you want 8 2/3 divided by 1 1/5 =

26/3 / 6/5

= 26/3 * 5/6 = 130 / 18

7 and 4/18 containers

4 0

3 years ago

I provided the answers I just need you to show work. I’ll even mark you the Brainliest!

Sindrei [870]

The intercepts and the graph on your worksheet are not correct. Please see below for details:

$x^2-2x-3=0$ has solutions at x=-1 and x=3 (use the quadratic formula to solve). That means these are the x-intercepts, namely points:

(-1,0) and (3,0).

The y-intercept comes from setting x=0 and calculating the y value:

$y=0^2-2\cdot0-3=-3$

so the y-intercept is (0,-3).

Now to the graph: Based on the form of the function we can see this is a quadratic function and its graph will be a parabola. You can reformat the expression in the following form

$y = x^2-2x-3=(x-1)^2-4$

and that will indicate that the apex of the parabola (open up) will be at the point (1,-4).

Knowing the apex, the x intercepts, and the y intercept, we can graph it now.

Graph is in the image attached.

6 0

2 years ago

X2 – 12x + 37 = 0 in simplest a + bi form

Andreas93 [3]

Answer:

x=6+1

Step-by-step explanation:

4 0

3 years ago

Integrate the following:<br><img src="https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Cint%20%5C%3A%20%20%5Ctan%28x%29%20%20%20%5

Korvikt [17]

Answer:

$\huge \boxed{\red{ \boxed{ - \cos(x) + C}}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

integration
PEMDAS

<h3>tips and formulas:</h3>

$\tan( \theta) = \dfrac{ \sin( \theta) }{ \cos( \theta) }$
$\sf \displaystyle \int \sin(x) \: dx = - \cos(x) + C$

<h3>let's solve:</h3>

$\sf \: rewrite \: \tan( \theta) \: as \: \dfrac{ \sin( \theta) }{ \cos( \theta) } : \\ = \displaystyle \int \: \frac{ \sin(x) }{ \cos(x) } \cos(x) \: dx \\ = \displaystyle \int \: \frac{ \sin(x) }{ \cancel{\cos(x) }} \: \cancel{ \cos(x)} \: dx \\ = \displaystyle \int \: \sin(x) \: dx$
$\sf \: use \: the \: formula : \\ \sf \displaystyle - \cos(x)$
$\sf add \: constant : \\ - \cos(x) + C$