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Ghella [55]
3 years ago
6

The wavelength of a wave is the distance between

Physics
1 answer:
Neko [114]3 years ago
4 0
Two consecutive crests
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A model rocket rises with constant acceleration to a height of 4.2 m, at which point its speed is 27.0 m/s. How much time does i
geniusboy [140]

Answers:

a) t=0.311 s

b) a=86.847 m/s^{2}

c) y=1.736 m

d) V=17.369 m/s

Explanation:

For this situation we will use the following equations:

y=y_{o}+V_{o}t+\frac{1}{2}at^{2} (1)  

V=V_{o} + at (2)  

Where:  

y is the <u>height of the model rocket at a given time</u>

y_{o}=0 is the i<u>nitial height </u>of the model rocket

V_{o}=0 is the<u> initial velocity</u> of the model rocket since it started from rest

V is the <u>velocity of the rocket at a given height and time</u>

t is the <u>time</u> it takes to the model rocket to reach a certain height

a is the <u>constant acceleration</u> due gravity and the rocket's thrust

<h2>a) Time it takes for the rocket to reach the height=4.2 m</h2>

The average velocity of a body moving at a constant acceleration is:

V=\frac{V_{1}+V_{2}}{2} (3)

For this rocket is:

V=\frac{27 m/s}{2}=13.5 m/s (4)

Time is determined by:

t=\frac{y}{V} (5)

t=\frac{4.2 m}{13.5 m/s} (6)

Hence:

t=0.311 s (7)

<h2>b) Magnitude of the rocket's acceleration</h2>

Using equation (1), with initial height and velocity equal to zero:

y=\frac{1}{2}at^{2} (8)  

We will use y=4.2 m :

4.2 m=\frac{1}{2}a(0.311)^{2} (9)  

Finding a:

a=86.847 m/s^{2} (10)  

<h2>c) Height of the rocket 0.20 s after launch</h2>

Using again y=\frac{1}{2}at^{2} but for t=0.2 s:

y=\frac{1}{2}(86.847 m/s^{2})(0.2 s)^{2} (11)

y=1.736 m (12)

<h2>d) Speed of the rocket 0.20 s after launch</h2>

We will use equation (2) remembering the rocket startted from rest:

V= at (13)  

V= (86.847 m/s^{2})(0.2 s) (14)  

Finally:

V=17.369 m/s (15)  

5 0
3 years ago
Whats the purpose of the metal strip under a car?
mezya [45]

Answer:

It ensures the doors seal properly when closed. This seal will fend off the elements, and prevent water from leaking inside the vehicle. It is further used on windows to seal and protect the windows.

Explanation:

3 0
3 years ago
How does moon appears to mov e across the night sky
trasher [3.6K]

Answer:

The moon moves because the earth rotates around its axis of rotation. Although the moon moves too around its orbit, the speed is too small to notice. In other words, the moon's position changes insignificantly, however, the earth rotates fast enough to notice.

7 0
2 years ago
A string with tension Ft= 10 N, with one end pinned and the other end free, is used to produce a wave supplied by a driving freq
Hitman42 [59]

To solve the problem it is necessary to apply the theory of sine waves. The wavelength λ of a sinusoidal waveform traveling at constant speed v is given by

\lambda = \frac{v}{f}

Where,

v= velocity

f = frequency

Re-arrange to find v, we have

v = f\lambda

PART A ) Replacing with our values we have,

v = (10*10^3)(0.01)

v = 100m/s

PART B) In the case of the period we know that it is defined as a function of frequency as,

T= \frac{1}{f}

That is to say that using the previously given values we have that the period in seconds is,

T=1*10^{-4}s

PART C) Finally the transverse wave velocity is given by,

v=\sqrt{\frac{T}{\mu}}

Where,

T= Period

\mu = Linear mass density

Re-arrange to find \mu,

\mu = \frac{T}{v^2}

\mu = \frac{1*10^{-4}}{100^2}

\mu = 1*10^{-8}kg/m

5 0
3 years ago
The ball is launched with total initial energy Einitial = mgho. When it reaches the bottom of the hoops, it now has a potential
NeX [460]

Answer:

  K = m g (h₀ - h_plat)

Explanation:

Let's use energy conservation to solve this problem, write the energy at two points of interest

Initial. Higher

          E_initial = m g h₀

Final. Lower

          E_end = K + Ep

          E_end = ½ m v² + m g h_plat

Energy is conserved

          E_initial = E_end

          m g h₀ = K + m g h_plat

          K = m g (h₀ - h_plat)

4 0
3 years ago
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