Answer:
a) 42.9 m/s
b) 41.6m
Explanation:
a)
solving the eq we get
v=42.9 m/s
b) <em>here,</em>
when put in y(t) it gives y=44.6 m so result is
h=44.6-3= 41.6m
B.) Carbon Dioxide because the carbon is surrounded by oxygen
B!
This is because gravitational pull energy needs a height. The higher the height the higher the energy.
From kinematic relation d = vi t + 1/2 at^2 , a = 2d/t^2 since it starts from rest . Acceleration does not depend on the mass. a = 2* 2.5 / (1.47)^2 = 2.3139 m/s^2.
Acceleration down the slide is due to the parallel component of gravity force. Friction opposes this force and acts up the inclined plane. mg sin theta - f = ma. Friction = f = (2.45 * 9.8) sin 30.5 - (2.45)(2.3139) = 6.5169 N.
Normal force = mg cos 30.5 = (2.45*9.8)* cos 30.5 = 20.6877 N. Friction = uk N. coefficient of friction = = friction / N = 6.5169 / 20.6877 = 0.32.
When it reaches the bottom of the slide, vf = vi + at = 0 + ( 2.3139)(1.47) = 3.4014 m/s = velocity at the bottom