The gas releases an amount of heat equal to -225 J
Explanation:
The change in internal energy of a diatomic gas is given by:
where
n is the number of moles
R is the gas constant
is the change in temperature
For this gas we have:
n = 0.235 mol
So, the change in internal energy of the gas is
Now we can use the 1st law of thermodynamics to find the heat absorbed/released by the gas:
where
Q is the heat absorbed by the gas
W is the work done by the gas
Here we have:
Solving for Q, we find:
Where the negative sign means the heat has been released by the gas.
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The friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 × 10^8 respectively. Also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 × 10^8 respectively.
<h3>How to determine the friction factor</h3>
Using the formula
μ = viscosity = 0. 06 Pas
d = diameter = 120mm = 0. 12m
V = velocity = 1m/s and 3m/s
ρ = density = 0.9
a. Velocity = 1m/s
friction factor = 0. 52 ×
friction factor = 0. 52 ×
friction factor = 0. 52 × 0. 55
friction factor
b. When V = 3mls
Friction factor = 0. 52 ×
Friction factor = 0. 52 ×
Friction factor = 0. 52 × 0. 185
Friction factor
Loss When V = 1m/s
Head loss/ length = friction factor × 1/ 2g × velocity^2/ diameter
Head loss = 0. 289 × × ×
Head loss = 1. 80 × 10^8
Head loss When V = 3m/s
Head loss = × × ×
Head loss = 5. 3× 10^8
Thus, the friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 ×10^8 respectively also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 ×10^8 respectively.
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<span>A transverse wave is a moving wave that consists of oscillations occurring perpendicular (or right angled) to the direction of energy transfer. If a transverse wave is moving in the positive x-direction, its oscillations are in up and down directions that lie in the y–z plane. Light is an example of a transverse wave.</span>
Answer:
five characteristics: Wavelength, Amplitude, Time-Period, Frequency and Velocity or Speed