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3 years ago

Find a constant c for which p(z ≥ c.= 0.1587. round the answer to two decimal places.

1 answer:

8 0

What you see in the z score table is P(z< a constant), for P( z≥ a number), subtract the probability from 1:
1-0.1587=0.8413
on the z score table, you will see that p(z<1.00)=0.8413
so c=1.00

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If the sum of two consecutive odd number is 12 find them

Fiesta28 [93]

Answer:

5 and 7

Step-by-step explanation:

Fast and loose: 12 is written as a sum of two odd numbers as 1+11; 3+9; 5+7. The only consecutive pair is 5 and 7

Let's use algebra: let's call 2n+1 the first and 2n+3 the second.

Their sum is 2n+1 +2n+3 = 4n+4 = 12. Thus, n+1=3 and n= 2. It means the 2 numbers are 2x2+1 =5 and 2x2+3 =7

5 0

3 years ago

A tree casts a shadow that is 20 feet long. the angle of elevation from the end of the shadow to the top of the tree is 66 degre

Dmitriy789 [7]

I believe it is 45 feet. Equation: tan(66)=20/x. Change it to 20 tan(66) in a calculator and that is how you get it.

3 0

4 years ago

Read 2 more answers

X/x-2 + x-1/x+1= -1 Can someone walk me through the steps of this problem? Much appreciated. :)

stealth61 [152]

Answer:

x = 0 or x = 1

Step-by-step explanation:

Given equation:

$\dfrac{x}{x-2}+\dfrac{x-1}{x+1}=-1$

Multiply the two denominators to get the same denominator:

Multiply the numerator of the first fraction by the denominator of the second fraction to get the new numerator of the first fraction.

Multiply the numerator of the second fraction by the denominator of the first fraction to get the new numerator of the second fraction.

$\implies \dfrac{x(x+1)}{(x-2)(x+1)}+\dfrac{(x-2)(x-1)}{(x-2)(x+1)}=-1$

Add the numerators and keep the denominator so that there is now one fraction:

$\implies \dfrac{x(x+1)+(x-2)(x-1)}{(x-2)(x+1)}=-1$

Simplify the numerator by expanding the brackets:

$\implies \dfrac{x^2+x+x^2-3x+2}{(x-2)(x+1)}=-1$

$\implies \dfrac{2x^2-2x+2}{(x-2)(x+1)}=-1$

Simplify the denominator by expanding the brackets:

$\implies \dfrac{2x^2-2x+2}{x^2-x-2}=-1$

Multiply both sides by the denominator of the left side:

$\implies 2x^2-2x+2=-1(x^2-x-2)$

Simplify and move everything to the left side:

$\implies 2x^2-2x+2=-x^2+x+2$

$\implies 3x^2-3x=0$

Factor:

$\implies 3x(x-1)=0$

Therefore:

$\implies 3x=0 \implies x=0$

$\implies x-1=0 \implies x=1$

Therefore, x = 0 or x = 1

8 0

2 years ago

Read 2 more answers

2a(squared)b(cubed) and -4a(squared)b(cubed) are like terms true or false

coldgirl [10]

Answer:

True

Step-by-step explanation:

2a^2b^3 and -4a^2b^3 are like terms because the variable parts (a^2 and b^3) are identical.

4 0

4 years ago

Solve the system of equations using substitution y=x-1 and y=-2x+5

pav-90 [236]

Since the two equations equal y, set them equal to each other.

x-1=-2x+5

From there, solve for x.

First get x on one side, by using the addition property of equality.

x-1=-2x+5
3x-1=5

Isolate x by adding 1.
3x=6

Lastly get x all by itself by dividing each side by 3.
x=2

You can now substitute your x-value, 2, into one of the equations (or both, if you wish; either one will result in the same answer.)

y=x-1
y=2-1
y=1

OR

y=-2x+5
y=-2(2)+5
y=-4+5
y=1

Final answer:
x=2 and y=1

Any questions or anything you would like me to clarify, feel free to ask :)

7 0

3 years ago