What is the value of this expression 1/5-^5?

Mathematics

1 answer:

densk [106]3 years ago

7 0

Answer:

B.3125

Step-by-step explanation:

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jasenka [17]

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show that the points (1 ,7) ,(4, 2), (-1, -1) and (-4, 4) taken in order are the vertics of a square. Also find its area

OLga [1]

Answer:

Step-by-step explanation:

A (1 ,7) , B(4, 2), C(-1, -1) and D(-4, 4)

Find the distance of sides using distance formula.

Distance = $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

A (1 ,7) , B(4, 2)

$AB = \sqrt{(4-1)^{2}+(2-7)^{2}}\\\\ =\sqrt{3^{2}+(-5)^{2}}\\\\ \\ = \sqrt{9+25}=\sqrt{34} units\\\\\\\\BC = \sqrt{(-1-4)^{2}+(-1-2)^{2}}\\\\ =\sqrt{(-5)^{2}+(-3)^{2}} = \sqrt{25+9}=\sqrt{34} units\\\\\\CD = \sqrt{(-4-[-1])^{2}+(4-[-1])^{2}}\\\\=\sqrt{(-4+1)^{2}+(4+1)^{2}}\\\\=\sqrt{(-3)^{2}+(5)^{2}}\\\\=\sqrt{9+25} = \sqrt{34} units\\\\\\AD = \sqrt{(-4-1)^{2}+(4-7)^{2}}\\\\=\sqrt{(-5)^{2}+(-3)^{2}} =\sqrt{25+9} = \sqrt{34} units$