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gayaneshka [121]
4 years ago
15

How many ways are there to distribute six different toys to three different children such that each child gets at least one toy?

Mathematics
1 answer:
Kruka [31]4 years ago
6 0
Give two toys to each child
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Solve for x.<br><br> x+23=−22<br><br> someone help
BaLLatris [955]

Answer:

x = - 45

Step-by-step explanation:

x+23(-23)=−22 (-23)First subtract 23 from both sides

x = - 45

7 0
3 years ago
Classify each figure on the triangle
ipn [44]
All the triangles are isosceles meaning that they have to sides that are equal 
5 0
3 years ago
Read 2 more answers
Please help!!!<br> What is the area of the trapezoid?
olga nikolaevna [1]
330m^2 is the answer
6 0
3 years ago
Calculate the number of ways to form a set of three distinct items such that no two of the selected items are in the same row or
Eddi Din [679]

Answer:

1200

Explanation:

Order does not matter, if we said xyz order, it would still not make a difference if it was zyx or yzx hence we use the combination formula:

nCr = n! / r! * (n - r)!

where n= total number of items

r= number of items chosen at a time

Combinations are used when the order of events do not matter in calculating the outcome.

We calculate using the formula:

(30×20×12)÷3!=1200

There are therefore 1200 ways for the three distinct items to not be in same row or column

8 0
3 years ago
How would you go about finding the solution to this system of three equations in three variables? Be specific. For example, you
kupik [55]
I:2x – y + z = 7
II:x + 2y – 5z = -1
III:x – y = 6

you can first use III and substitute x or y to eliminate it in I and II (in this case x):
III: x=6+y
-> substitute x in I and II:
I': 2*(6+y)-y+z=7
12+2y-y+z=7
y+z=-5

II':(6+y)+2y-5z=-1
3y+6-5z=-1
3y-5z=-7

then you can subtract II' from 3*I' to eliminate y:
3*I'=3y+3z=-15

3*I'-II':
3y+3z-(3y-5z)=-15-(-7)
8z=-8
z=-1

insert z in II' to calculate y:
3y-5z=-7
3y+5=-7
3y=-12
y=-4

insert y into III to calculate x:
x-(-4)=6
x+4=6
x=2

so the solution is
x=2
y=-4
z=-1
3 0
4 years ago
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