Answer:
YET
Step-by-step explanation:
TO DECRYPT DKA USING THE CAESAR SHIFT CIPHER STARTING WITH 5 SHIFTS.
TO DO THIS DECRYPTION, WE'RE GOING TO LOOP THE ALPHABETS.
D = LOOPING THIS LETTER 5 TIMES, WE HAVE C - B - A - Z - Y.
SO, D IS DECRYPTED AS Y
GOING FURTHER, THE ENCRYPTION SHIFTS BY AN ADDITIONAL SPACE. THIS MEANS, IF THE FIRST "Y" WAS ENCRYPTED IN 5 SPACES TO GET D, AND AN ADDITIONAL SPACE WAS ADDED TO THE NEXT ALPHABET, IT BECOMES 6.
K IS THEN DECRYPTED AS
K = J - I - H - G - F - E
K IS DECRPYTED AS E
GOING FURTHER, THE NEXT WAS ENCRYPTED WITH AN ADDITIONAL SPACE EVEN MORE, SO, A IS DECRPYTED AS
A = Z - Y - X - W - V - U - T.
THUS, DKA IS DECRYPTED AS YET
Answer:
60
Step-by-step explanation:
18 /30 is .6. So the answer would be 60 percent
<span>Based in the information given in the problem, you must apply the The Angle Bisector Theorem. Let's call the triangle: "ABC"; the internal bisector of the angle that divides its opposite side: "AP"; and "x": the longest and shortest possible lengths of the third side of the triangle.
If BP= 6 cm and CP= 5 cm, we have:
BP/CP = AB/AC
We don't know if second side of the triangle (6.9 centimeters long) is AB or AC, so:
1. If AB = 6.9 cm and AC = x:
6/5 = 6.9/x
x = (5x6.9)/6
x = 5.80 cm
2. If AC= 6.9 cm and AB= x:
6/5 = x/6.9
x = 6.9x6/5
x = 8.30 cm
Then, the answer is:
The longest possible length of the third side of the triangle is 8.30 cm and the and shortest length of it is 5.80 cm.</span>
Building and solving an equation to model the situation, it is found that it takes 4 min for the prairie dog to reach 13 feet underground.
- Initially, the dog is 5 feet underground.
- Each minute, the dog goes 2 more feet underground.
Hence, the underground height of the dog after t seconds is given by:

The time it takes for the dog to reach 13 feet underground is <u>t for which h(t) = 13</u>, hence:





It takes 4 min for the prairie dog to reach 13 feet underground.
A similar problem is given at brainly.com/question/25290003
Answer: I added an attachment of what the graph should look like! :)
Step-by-step explanation: