The shaded area in the image is 86.1 square inches.
<h3>
How to get the shaded area?</h3>
Remember that for a circle of diameter D, the area is given by:
A = pi*(D/2)²
Where pi = 3.14, and here we have half-circles, so we need to add a factor 0.5
The area of the shaded figure, the area of the shaded figure will be the area of the half circle with diameter of 17in minus the area of the half circle with a diameter of 8.5 in, so the area is:
area = 0.5*3.14*(17in/2)² - 0.5*3.14*(8.5in/2)² = 86.1 in²
Learn more about area:
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Is this simultaneous equations?
if yes then the first step is
make one of the unknown as the subject
If you need part A, draw a person and label them 6 feet tall and a shadow coming off of him that is five feet long and draw a basketball hoop that and label it X feet tall and draw a shadow coming from it that is 8 feet long. To solve, you use proportions 6/5=X/8 solving this you get X=9.6 feet which is the height of the rim. Therefore, the rim does not meet regulation height, since the required height (10 feet) is greater than the actual height (9.6 feet).
Checking the <span>discontinuity at point -4
from the left f(-4) = 4
from the right f(-4) = (-4+2)² = (-2)² = 4
∴ The function is continues at -4
</span>
<span>Checking the <span>discontinuity at point -2
from the left f(-2) = </span></span><span><span>(-2+2)² = 0
</span>from the right f(-2) = -(1/2)*(-2)+1 = 2
∴ The function is jump discontinues at -2
</span>
<span>Checking the <span>discontinuity at point 4
from the left f(4) = </span></span><span><span>-(1/2)*4+1 = -1
</span>from the right f(4) = -1
but there no equality in the equation so,
</span><span>∴ The function is discontinues at 4
The correct choice is the second
point </span>discontinuity at x = 4 and jump <span>discontinuity at x = -2</span>
Answer:
KL = 5.25
LJ = 6
Step-by-step explanation:
i don’t know the first one
