<span>So you have composed two functions,
</span><span>h(x)=sin(x) and g(x)=arctan(x)</span>
<span>→f=h∘g</span><span>
meaning
</span><span>f(x)=h(g(x))</span>
<span>g:R→<span>[<span>−1;1</span>]</span></span>
<span>h:R→[−<span>π2</span>;<span>π2</span>]</span><span>
And since
</span><span>[−1;1]∈R→f is defined ∀x∈R</span><span>
And since arctan(x) is strictly increasing and continuous in [-1;1] ,
</span><span>h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]</span><span>
Meaning
</span><span>f:R→[arctan(−1);arctan(1)]=[−<span>π4</span>;<span>π4</span>]</span><span>
so there's your domain</span>
There's no question there. You didn't attach the pic
Answer:
k =4/5
Step-by-step explanation:
Answer:
0.5 ft^2
Step-by-step explanation:
The area in square inches is (6 in )(12 in) = 72 in^2.
Recall that 1 ft^2 = 144 in^2.
Then
72 in^2 1 ft^2
--------------- * --------------- = 0.5 ft^2
1 144 in^2
X×2=10
X=10÷2
X=5
Proof: 5×2=10
