Answer:
(b) The interquartile range of B is greater than the interquartile range of A.
(d) The median of A is the same as the median of B.
Explanation:
Given


So:

Required
Select all true statements
(a) & (d) Median Comparisons


Arrange the data:




--- average of 5th and 6th

Option (d) is correct because both have a median of: 2
(b) & (c) Interquartile Range Comparisons


First, calculate the lower quartile (Q1)
[Odd n]
[Even n]


This means that:


Next, calculate the upper quartile (Q3)
[Odd n]
[Even n]

This means that:

The interquartile range is 
So, we have:


(b) is true because B has a greater IQR than A
(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.
The upper quartile and the interquartile range of A and B are not equal
Answer:Biological structures are able to adapt their growth to external mechanical stimuli and impacts. For example, when plants are under external loads, such as wind force and self-weight, the overloaded zones are reinforced by local growth acceleration and the unloaded zones stop growing or even shrink. Such phenomena are recorded in the annual rings of trees. Through his observation of the stems of spruce, K. Metzger, a German forester and author, realized that the final goal of the adaptive growth exhibited by biological structures over time is to achieve uniform stress distribution within them. He published his discovery in 1893.12 A team of scientists at Karlsruhe Research Centre adopted Metzger's observations and developed them to one single design rule: the axiom of uniform stress. The methods derived from this rule are simple and brutally successful like nature itself. An excellent account of the uniform-stress axiom and the optimization methods derived from it is given by Claus Mattheck in his book ‘Design in Nature’.13 The present study utilizes one of these methods, stress-induced material transformation (SMT), to optimize the cavity shape of dental restorations.
Explanation:
Answer:
The larva gets dark pigment.
Explanation:
If scientists purposely injected an excess concentration of these proteins in the larva, the larva gets deep dark colour because this protein is responsible for the pigment colour in the larva of Drosophila. By increasing the protein concentration the pigment will also have a very dark colour. So we can conclude from this that increasing the amount of protein causes increase in the pigment colour.