X= 3 y=3
(3)2x+y=9
4x-3y=3
6x+3y=27
4x-3y=3
——————
10x=30
—————-
10
x=3
2(3)+y=9
6+y=9
-6. -6
y=3
I think the answer is -6i and 2-5i
If I remember correctly imaginary numbers must also have their conjugate as a zero as well
Hope this helps
Answer:
infinite
Step-by-step explanation:
name two, and then find a third in between them.
you can repeat that as often as you want.
Answer:
C.
Step-by-step explanation:
-3 7/8 rounds down to -4
4.63 rounds up to 5
-4 x 6 + 5
-24 + 5
-19
her answer (-19.14) also rounds to -19
So yes, it is reasonable and the correct response is C.
