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4 years ago

WILL RATE BRAINLIEST

Mathematics

1 answer:

LUCKY_DIMON [66]4 years ago

6 0

Answer:

if your question is to find the vertical height of D, ans is 5

Step-by-step explanation:

You might be interested in

A rectangular auditorium seats 1702 people. The number of seats in each row exceeds the number of rows by 9. Find the number of

klemol [59]

We have been given that a rectangular auditorium seats 1702 people. Also, the number of seats in each row exceeds the number of rows by 9.

Let us assume that there are x rows in the auditorium. Therefore, there must be (x+9) seats in the each row. This will also be equal to the number of columns in the auditorium.

Therefore, we can set up an equation as:

$x(x+9)=1702\\x^{2}+9x=1702\\x^{2}+9x-1702=0$

We can now factor this quadratic as shown below:

$x^{2}+9x-1702=0\\(x-37)(x+46)=0$

Upon solving this equation, we get:

$x=-46,37$

Since number of rows cannot be negative. Therefore, there must be 37 rows in the auditorium. And hence, the number of seats in each row will be 37+9=46 seats.

8 0

3 years ago

How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird

NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

$\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}$

Then

$Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\$

Note that since

$F \cap R=\varnothing$ , $Perm(F)\cap Perm(R)\ne \varnothing$

But since

$B \cap R \ne \varnothing$ , $Perm(B)\cap Perm(R)= \varnothing$

and

$B \cap F \ne \varnothing$ , $Perm(B)\cap Perm(F)= \varnothing$

Since

$|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\$

where $|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}$

and

$|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}$

What we are looking for is the number of permutations of the 26 letters of the alphabet that do not contain the strings fish, rat or bird, or

$|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}$

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0

3 years ago

A 5.9-foot-tall-man stands near a 12-foot statue. The man places a mirror on the ground a certain distance from the base of the

jeka94

Answer:

14.24 foot far is the mirror from the base of the statue.

Step-by-step explanation:

Proportion states that the two ratios or fractions are equal.

As per the statement:

See the diagram as shown below:

Height of a boy = 5.9 foot tall

Height of a statue = 12 foot.

Distance of a boy from the mirror = 7 feet.

Let x be the distance of the mirror from the base of the statue.

then by definition of proportion we have;

$\frac{\text{Height of a boy}}{\text{Distance of a boy from the mirror}}= \frac{\text{Height of a statues}}{\text{Distance of mirror from the base of the statue} }$