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Sloan [31]
3 years ago
7

Suppose the Willard gold nugget was turned into 4 equal sized gold bricks. If one of the bricks was sold how many ounces of the

Willard nugget would be left?

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
8 0
788/4 = 197

788 - 197 = 591
alexgriva [62]3 years ago
8 0
788/4= 197; 197 ounces for each golden brick. 

---- 197x4= 788 so if 197 oz was sold then 788-197= 591oz.

 > There would only be 591 oz left
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Yasmin swims at a constant rate of 2 km/h for 2.5 h. How far does Yasmin swim? 4.5 km 5 km 6 km 6.5 km
Neporo4naja [7]
She swims for 2.5 hours at a rate of 2 km/hr
Multiply 2.5 * 2 = 5 km
3 0
2 years ago
The table shows information about the masses of some dogs. a) Work out the minimum number of dogs that could have a mass of more
V125BC [204]

Information regarding various dogs' masses is displayed in the table.

(a) 4 bare minimum number of dogs that could weigh more than 27 kg.

(b) 17 dogs, in total, may weigh more than 27 kg.

Given that,

Information regarding various dogs' masses is displayed in the table.

(a)Calculate the bare minimum number of dogs that could weigh more than 27 kg.

(b)Calculate how many dogs, in total, may weigh more than 27 kg.

(a) 4 bare minimum of dogs that could weigh more than 27 kg.

Because the minimum number so lets assume that all dogs in 20≤x<30 are less then 27.

Therefore, 4 bare minimum of dogs that could weigh more than 27 kg.

(b) 17 dogs, in total, may weigh more than 27 kg.

Because the maximum number so lets assume that all dogs in 20≤x<30 are more then 27.

4+13=17

Therefore,17 dogs, in total, may weigh more than 27 kg.

To learn more about numbers visit: brainly.com/question/17429689

#SPJ1

6 0
1 year ago
Can some help me fast!
Mice21 [21]

Answer:

5x +2y =38

5(6) +2y = 38

30 +2y= 38

2y= 8

y= 4

(6, 4)

5(0) +2y =38

2y= 38

y= 19

(0,19)

5(-2) +2y= 38

-10 +2y =38

2y= 48

y=24

(-2,24)

7 0
2 years ago
Dylan wants to buy both the tablet and
nignag [31]

Answer:

108$

Step-by-step explanation:

6 0
3 years ago
A game involves rolling a fair six-sided die. If the number facing upward on the die is a whole number multiple of three, the pl
BaLLatris [955]
There is only two multiples of three on a six-sided die, the 3 side, and the 6 side.

3 x 20 = 60
6 x 20 = 120
120 + 60 = 180

$180.00 is your possible winnings total, but the question asks for your expected value on EACH roll, so you divide 180 by 6(sides on a die) to get your final answer

180/6 = 30

ANSWER: D. $30.00




5 0
2 years ago
Read 2 more answers
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