What is 4/5y+1/8x=4 in standard form? really need the help!!!

3 dollar 8 dimes +1 dollar 2 quarters 5 pennies

zepelin [54]

Answer:

5.35

Step-by-step explanation:

1.55 +3.80 = 5.35

7 0

3 years ago

Three friends met for a book club at a coffee shop, each friend ordered a cup of coffee and two donuts. the total of the order w

4vir4ik [10]

Answer:

$Cost\ of\ donut=\frac{49}{24}\approx \$2.042\\\\cost\ of\ donuts=\frac{49}{4}\approx \$12.25$

Step-by-step explanation:

a.

$Let\ cost\ of\ coffee=y\\\\cost\ of\ one\ donut=x\\\\Each\ friend\ buy\ one\ coffee\ and\ two\ donuts\\\\Amount\ for\ 1\ friend=Cost\ of\ coffee+2\times cost\ of\ donut\\\\Amount\ for\ 1\ friend=y+2x\\\\Amount\ required\ for\ 3\ friend=3\times Amount\ for\ 1\ friend\\\\Amount\ required\ for\ 3\ friend=3\times (y+2x)\\\\Amount\ required\ for\ 3\ friend=3y+6x\\\\Total\ bill=\$ 22\\\\3y+2x=22\\\\Given\ cost\ of\ coffee=\$3.25\\\\y=\$3.25$

$Hence\ solution\ of\ following\ system\ of\ equation\ will\ give\ cost\ of\ donut:\\\\3y+6x=22\\\\y=3.25\\\\\\Substitute\ y=3.25\ in\ first\ equation\\\\3\times 3.25+6x=22\\\\9.75+6x=22\\\\6x=22-9.75\\\\6x=12.25\\\\x=\frac{12.25}{6}\\\\x=\frac{49}{24}\approx \$2.042\\\\Cost\ of\ donut=\frac{49}{24}\approx \$2.042$

See attached diagram.

b.

$Each\ friend\ takes\ 2\ donuts\\\\Total\ donuts=Number\ of\ friends\times 2\\\\Total\ donuts=3\times 2=6\\\\cost\ of\ donuts=number\ of\ donuts\times cost\ of\ 1\ donut\\\\cost\ of\ donuts=6\times \frac{49}{24}\\\\cost\ of\ donuts=\frac{49}{4}\approx \$12.25$

5 0

3 years ago

1/10 of ____ is 10 times as much as 8

Vanyuwa [196]

The answer is 800.
To find this, multiply 10 times 8 to find the number you are dividing. (80) now, multiply 80 by 10. (800)
<span>1/10 of 800 is 80, which is ten times as much as 8.</span>

8 0

2 years ago

web based software company is interested in estimating the proportion of individuals who use the Firefox browser. In a sample of

nata0808 [166]

<h2>Answer with explanation:</h2>

Let $\hat{p}$ denotes the sample proportion.

As per given , we have

n= 200

$\hat{p}=\dfrac{30}{200}=0.15$

Critical value for 99% confidence : $z_{\alpha/2}=2.576$

Confidence interval for population proportion :-

$\hat{p}\pm z_{\alpha/2} \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.15\pm (2.576)(\sqrt{\dfrac{0.15(1-0.15)}{200}})\\\\\approx0.15\pm0.065\\\\=(0.15-0.065,\ 0.15+0.065)\\\\=(0.085,\ 0.215)$

Hence, a 99% confidence interval for the proportion of all individuals that use Firefox: $(0.085,\ 0.215)$

The lower limit on the 99% confidence interval = 0.085

6 0

2 years ago

Plzzzzzzzzzzzzzzzzzzzzzzzzzzz neeeed helpppppppppppppppppppppp

Olegator [25]

Answer:

D

Step-by-step explanation: hope this helps

4 0

2 years ago