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Setler79 [48]
4 years ago
10

If the diameter of an entire coconut is 5 inches, and the coconut meat is 1 inch thick, then there is room for approximately (bl

ank) to the third power of coconut milk. Which number correctly fills in the blank in the precious sentence?
Mathematics
1 answer:
svetoff [14.1K]4 years ago
6 0
The answer is 14.137 cubic inches.

For this case, the radius of whole coconut is 2.5 inches (which is 5 inches / 2).
You have to subtract the thickness of the coconut from this radius for you to get the volume of the space for coconut milk.

new radius = 2.5 - 1 = 1.5 inches

Volume = (4/3)(pi)(r^3)
= (4/3)(pi)(1.5^3)
= 14.137 cubic inches
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The patio shown has an area of 116 square feet. What is the value of h?
Oduvanchick [21]

Answer:

8 ft

Step-by-step explanation:

if we made this into a rectangle (pretend you chop off one of the triangles and glue it to the other one to make a long rectangle), the length would be 10+4.5, or 14.5. to find what h is, we can just divide 116 by 14.5. our answer is 8.

8 0
3 years ago
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

3 0
3 years ago
Read 2 more answers
How to do break even analysis​
Ksenya-84 [330]

Answer:

To calculate a break-even point based on units: Divide fixed costs by the revenue per unit minus the variable cost per unit. ...

When determining a break-even point based on sales dollars: Divide the fixed costs by the contribution margin.

7 0
3 years ago
Ann bought 6 CDs that were each the same price. Including sales tax, she paid a total of 93.60. Of that total, 4.20was tax. What
Mariulka [41]
If you do 93.60-4.20=89.40. Then you do 89.40 divided by 6= 14.90 so each cd before tax would be $14.90.
7 0
3 years ago
PLS HELP ME, I REALLY NEED THIS RIGHT NOW, 100 POINTS, IF YOU ANSWER WITH NO EXPLANATION, OR ANSWER FOR THE POINTS YOU WILL BE R
lesya692 [45]

Answer: Here I simplified it and I think its right.

Step-by-step explanation:

7 0
3 years ago
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