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IceJOKER [234]
3 years ago
14

Evaluate 6t - 20-32u when t = 6 and u = 1/5

Mathematics
2 answers:
Papessa [141]3 years ago
7 0

Answer:

48/5

Step-by-step explanation:

6t - 20-32u

Let t= 6 and u = 1/5

6*6 - 20 -32(1/5)

Multiply

36 -20 -32/5

16 - 32/5

Get a common denominator

80/5  -32/5

48/5

RoseWind [281]3 years ago
7 0

Answer:

48/5= 9 4/5

Step-by-step explanation:

first substitute the variable

6(6)-20-32(1/5)

36-20-32/5

16-32/5

get the both numbers to have the same denominator

16 times 5/5= 80/5

now subtract the both numbers

80/5-32/5= 48/5

48/5= 9 4/5

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Step by step
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1 year ago
Enter the value of p so the expression 5/6-1/3n is equivalent to p(5-2n)?
inna [77]
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3 years ago
(SHOW YOUR WORK PLZ AND EXPLAIN)
77julia77 [94]
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Read 2 more answers
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Alex73 [517]

Answer:

Step-by-step explanation:

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