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3 years ago

Evaluate 6t - 20-32u when t = 6 and u = 1/5

Mathematics

2 answers:

Papessa [141]3 years ago

7 0

Answer:

48/5

Step-by-step explanation:

6t - 20-32u

Let t= 6 and u = 1/5

6*6 - 20 -32(1/5)

Multiply

36 -20 -32/5

16 - 32/5

Get a common denominator

80/5 -32/5

48/5

RoseWind [281]3 years ago

7 0

Answer:

48/5= 9 4/5

Step-by-step explanation:

first substitute the variable

6(6)-20-32(1/5)

36-20-32/5

16-32/5

get the both numbers to have the same denominator

16 times 5/5= 80/5

now subtract the both numbers

80/5-32/5= 48/5

48/5= 9 4/5

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PLEASE HELP! WILL GIVE 70 POINTS!!

Tresset [83]

Answer:

$A=189\ mm^2$

Step-by-step explanation:

<u>Surface Areas </u>

Is the sum of all the lateral areas of a given solid. We need to compute the total surface area of the given prism. It has 5 sides, two of them are equal (top and bottom areas) and the rest are rectangles.

Computing the top and bottom areas. They form a right triangle whose legs are 4.5 mm and 6 mm. The area of both triangles is

$\displaystyle A_t=2*\frac{b.h}{2}=b.h=(4.5)(6)=27 mm^2$

The front area is a rectangle of dimensions 7.7 mm and 9 mm, thus

$A_f=b.h=(7.5)(9)=67.5 \ mm^2$

The back left area is another rectangle of 4.5 mm by 9 mm

$A_l=b.h=(4.5)(9)=40.5 \ mm^2$

Finally, the back right area is a rectangle of 6 mm by 9 mm

$A_r=b.h=(6)(9)=54 \ mm^2$

Thus, the total surface area of the prism is

$A=A_t+A_f+A_l+A_r=27+67.5+40.5+54=189\ mm^2$

$\boxed{A=189\ mm^2}$

4 0

3 years ago

Can you please help with this

sleet_krkn [62]

Answer:

Exercise 1 : a. 4 ; b. -4

Exercise 2 : a. +7 positive/right ; b. -7 ; c. -7 negative/left

Step-by-step explanation:

8 0

3 years ago

What is an example of when you would want consistent data and, therefore, a small standard deviation?

steposvetlana [31]

Answer:

12.1, 12.3,12.4,12.5,12.3,12.1,12.2

$\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271$

And for the standard deviation we can use the following formula:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And after replace we got:

$s = 0.1496$

And as we can ee we got a small value for the deviation <1 on this case.

Step-by-step explanation:

For example if we have the following data:

12.1, 12.3,12.4,12.5,12.3,12.1,12.2

We see that the data are similar for all the observations so we would expect a small standard deviation

If we calculate the sample mean we can use the following formula:

$\bar X=\frac{\sum_{i=1}^n X_i}{n}$

And replacing we got:

$\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271$

And for the standard deviation we can use the following formula:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And after replace we got:

$s = 0.1496$

And as we can ee we got a small value for the deviation <1 on this case.

8 0

3 years ago

You would like put up a fence around your rectangular backyard. You know that the length of your backyard

Bogdan [553]

Answer:

3 0

3 years ago

If R = 25 cm and S = 7 cm, what is the length of T?

Yakvenalex [24]

I think you need to post a graphic.

6 0

3 years ago