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3 years ago

Divide up the number 60 in 2:3:5 ratio.

Mathematics

2 answers:

andre [41]3 years ago

6 0

Answer:

Step-by-step explanation:

Dmitriy789 [7]3 years ago

4 0

I will do the homework for you but is is a quiz or test I can only do if it homework

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How do I solve 6/2 + 8/3

Xelga [282]

Answer:

The solved given fractional expression is $\frac{17}{3}$

Therefore the given fractional expression becomes

$\frac{6}{2}+\frac{8}{3}=\frac{17}{3}$

Step-by-step explanation:

Given fractional expression is $\frac{6}{2}+\frac{8}{3}$

To solve the given fractional expression as below :

$\frac{6}{2}+\frac{8}{3}$

$=3+\frac{8}{3}$

$=\frac{3\times 3+8}{3}$

( here taking the term 3 as LCM )

$=\frac{9+8}{3}$ ( by adding the sums here )

$=\frac{17}{3}$

$\frac{6}{2}+\frac{8}{3}=\frac{17}{3}$

Therefore the solved given fractional expression is $\frac{17}{3}$

Therefore the given fractional expression becomes

$\frac{6}{2}+\frac{8}{3}=\frac{17}{3}$

The solved given fractional expression is $\frac{6}{2}+\frac{8}{3}=\frac{17}{3}$

7 0

3 years ago

Solve the equation on the interval [0,2π). cos^4x=cos^4xcscx

Alisiya [41]

$\bf cos^4(x)=cos^4(x)csc(x)\\\\
-----------------------------\\\\
cos^4(x)=cos^4(x)\cfrac{1}{sin(x)}\implies cos^4(x)=\cfrac{cos^4(x)}{sin(x)}
\\\\\\
cos^4(x)sin(x)=cos^4(x)\implies cos^4(x)sin(x)-cos^4(x)=0
\\\\\\
cos^4(x)[sin(x)-1]=0\to 
\begin{cases}
cos^4(x)=0\to x=cos^{-1}(0)\\
----------\\
sin(x)-1=0\\
sin(x)=1\to x=sin^{-1}(1)
\end{cases}$

$\bf \measuredangle x = cos^{-1}(0)\implies \measuredangle x = 
\begin{cases}
\frac{\pi }{2}\\\\
\frac{3\pi }{2}
\end{cases}
\\\\\\
\measuredangle x=sin^{-1}(1)\implies \measuredangle x=\frac{\pi }{2}$

3 0

3 years ago

What is the slope of this line?

lianna [129]

The slope would be 0.

5 0

3 years ago

Read 2 more answers

Bruce bought a map that cost $7.35 he used a $10 bill to pay for his map what is the change

ankoles [38]

$2.65

You can get this by subtracting the 7.35 from the 10.

10 - 7.35 = 2.65

3 0

3 years ago

(01.03 MC)<br> Which of the following is a step in simplifying the expression<br> (Xy^4/x^-5y^5)^3

Sati [7]

$\displaystyle\tt\left(\frac{xy^4}{x^{-5}y^5}\right)^{-3} =\frac{x^{-3}y^{4\cdot(-3)}}{x^{-5\cdot(-3)}y^{5\cdot(-3)}}=\boxed{\tt\frac{x^{-3}y^{-12}}{x^{15}y^{-15}}}$

4 0

3 years ago