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Alecsey [184]
4 years ago
7

Which is a recursive formula for the sequence 99.4, 0, –99.4, –198.8, where f(1) = 99.4?

Mathematics
2 answers:
agasfer [191]4 years ago
6 0

Answer:

Which is a recursive formula for the sequence 99.4, 0, –99.4, –198.8, where f(1) = 99.4?

The answer will be : f(n + 1) = f(n) – 99.4, n ≥ 1

NNADVOKAT [17]4 years ago
5 0

f(x)= -99.4x + 198.8

f(1) = -99.4*1 + 198.8 = 99.4

f(2) = -99.4*2 + 198.8 = 0

f(3) = -99.4*3 + 198.8 = -99.4

<span>f(4) = -99.4*4 + 198.8 = -198.8
</span>

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<h3>What are trigonometric ratios?</h3>

The six trigonometric ratios of a right-angle triangle are Sin, Cos, Tan, Cosec, Sec and Cot. Trigonometric ratios are used to measure the sides of the right triangle.

Given that in ΔEFG, m∠E=30°, m∠F=60° and m∠G=90°.

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⇒\frac{\sqrt{3} }{2} =\frac{GE}{EF}

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Therefore, the statement EF=2.GF (Option A) and the statement \frac{\sqrt{3} }{2} .EF=GE (Option C) are true for the ΔEFG.

To learn more about trigonometric ratios visit:

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