A. Alright, we want to multiply one equation by a constant to make it cancel out with the second. Since the first equation has a "blank" y, let's multiply the first equation by <em>2</em>.
3x-y=0 → 2(3x-y=0) = 6x - 2y = 0
5x+2y=22
The answer for this part would be: 6x - 2y = 0 and 5x + 2y = 22
B. So now we combine them:
6x - 2y = 0
+ + +
5x + 2y = 22
= = =
11x + 0 = 22 ← The answer
C. Now that we have the equation 11x = 22, we solve for x
11x = 22 ← Divide both sides by 11
x = 2 ← The answer
D. Now that we have x=2, we plug that back in to 5x+2y=22 and solve for y:
5(2)+2y = 22
10 + 2y = 22
2y = 12
y = 6
<u>Therefore, the solution to this problem is x = 2 and y = 6</u>
Angle 1 = 134
angle 2 = 46
explanation:
angle 1 is a supplementary with 46
angle 2 is alternate interior with 46
Answer:
I believe the answer is 250. I hope this helps Bye!
9514 1404 393
Answer:
3, 0, 2, -2
Step-by-step explanation:
Put x=2 into each equation and solve for y.
<u>2 + y = 5</u>
y = 5 -2
y = 3
<u>3x +2y = 6</u>
3·2 +2y = 6
2y = 6 -6 = 0
y = 0
<u>2x +y = 6</u>
2·2 +y = 6
y = 6 -4
y = 2
<u>5x +3y = 4</u>
5·2 +3y = 4
3y = 4 -10 = -6
y = -2
Answer:
£110
Step-by-step explanation:
We know how much time it takes for a boiler and a radiator, and we need to know how much it will cost for 1 boiler and 4 radiators. We have an initial cost of £30, and since hes doing a boiler - which we know takes an hour - we can already add £20 for a start of £50.
Now, there are 4 radiators, that take 45 minutes each. We need to use this equation:
We divide by 60 because there are 60 minutes in an hour, and he charges by hour. So:
Now, to find out how much to charge, we need to figure out how much to add to the £50. Since it's £20 an hour, and it takes 3 hours to do the 4 radiators, we need to multiply:
Now we add our totals for a grand total of...
