Answer:
A' (3/2, -9/4)
B' (-3, 9/4)
C' (3/2, 9/4)
Step-by-step explanation:
1. You have the following coordinates of the vertices of the triangle ABC:
A (-2, 3) B (4, -3) C (-2, -3)
2. The given scale factor is -3/4, therefore, to calculate the coordinates of the triangle A'B'C', you must multiply each coordinate of the triangle ABC by the scale factor.
3. Therefore, you obtain that the the coordinates of the triangle A'B'C' are:
A'=((-2)(-3/4), (3)(-3/4))=(3/2, -9/4)
B'=(4(-3/4), (-3)(-3/4))=(-3, 9/4)
C'=((-2)(-3/4), (-3)(-3/4))=(3/2, 9/4)
