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nexus9112 [7]
3 years ago
7

Use cross multiplication to solve for x

Mathematics
2 answers:
iren [92.7K]3 years ago
6 0

Answer:

15

Step-by-step explanation:

andreyandreev [35.5K]3 years ago
5 0

Answer: x = 15

Explanation:

Step 1: Cross-multiply.

x /5  =  6 /2

x*(2) = (6)*(5)

2x=30

Step 2: Divide both sides by 2.

2x /2  =  30/2

x=15

hope this helps :D

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Use a truth table to show that P Qand (~PV Q) A (~QV P) are equivalen
kati45 [8]

Answer:  The given logical equivalence is proved below.

Step-by-step explanation:  We are given to use truth tables to show the following logical equivalence :

P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P)

We know that

two compound propositions are said to be logically equivalent if they have same corresponding truth values in the truth table.

The truth table is as follows :

P     Q      ∼P     ∼Q     P⇔ Q    ∼P ∨ Q     ∼Q ∨ P        (∼P ∨ Q)∧(∼Q ∨ P)

T     T         F        F             T            T                   T                       T

T     F         F        T             F             F                   T                       F

F     T         T        F             F            T                   F                       F

F     F         T        T             T            T                   T                       T

Since the corresponding truth vales for P ⇔ Q and (∼P ∨ Q)∧(∼Q ∨ P) are same, so the given propositions are logically equivalent.

Thus, P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P).

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Answer:

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Step-by-step explanation:

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100 Brainliest up for grabs to person who can answer all of these with no links:
kogti [31]

Using a discrete probability distribution, it is found that:

a) There is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.

b) There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.

c) The expected value is of 1.3 lawns mowed on a randomly selected day.

<h3>What is the discrete probability distribution?</h3>

Researching the problem on the internet, it is found that the distribution for the number of lawns mowed on a randomly selected dayis given by:

  • P(X = 0) = 0.2.
  • P(X = 1) = 0.4.
  • P(X = 2) = 0.3.
  • P(X = 3) = 0.1.

Item a:

P(X = 2) = 0.3, hence, there is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.

Item b:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2 = 0.8

There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.

Item c:

The expected value of a discrete distribution is given by the <u>sum of each value multiplied by it's respective probability</u>, hence:

E(X) = 0(0.2) + 1(0.4) + 2(0.3) + 3(0.1) = 1.3.

The expected value is of 1.3 lawns mowed on a randomly selected day.

More can be learned about discrete probability distributions at brainly.com/question/24855677

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2 years ago
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