Answer:
4). The Washington Monument is 169.2-m tall.
Step-by-step explanation:
4). We know this because...
person 1.8 0.7
---------- = ----- = -------
Wash. x 65.8
We then know to cross-multiply to get:
1.8(65.8) = 0.7x
Which simplifies down to:
118.44 = 0.7x
x = 169.2
Answer:
5). The pond is 180ft wide.
Step-by-step explanation:
5). We know this because...
90 120
----- = -------
135 x
We then know to cross-multiply to get:
90x = 120(135)
Which simplifies down to:
90x = 16200
x = 180
Answer:
6). The height of the clock tower is 13ft 9in.
Step-by-step explanation:
6). We know this because...
person 5.5 4
---------- = -------- = -----
clock x 10
We then know to cross-multiply to get:
5.5(10) = 4x
Which simplifies down to:
55 = 4x
x = 13.75 (13 ft 9 in)
Answer:
Fill the gaps in this sequence:
25 36 <u>49</u> 64 81 <u>100</u>
This sequence is the numbers 5, 6, 7, 8, 9, and 10 squared.
Work out the cube root of 343, then square it.
<u>49</u>
Since 7 cubed equals 343, then 7 squared is 49.
When you subtract one square number from another the answer is 7.
What are the two square numbers?
<u>16</u> and <u>9</u>
These are the only squares that fit the criteria.
Write down a number you can square to give an answer bigger than 200 but smaller than 300.
<u>15, 16, 17</u>
All of those answers work. 15² is 225, 16² is 256, and 17² is 289. You can choose any of them to enter in and it should work.
Answer:
y=-2x+12
Step-by-step explanation:
This is an equation in slope-intercept form:
y=mx+b (where m is the slope and b is the y-intercept)
We are given the slope, -2.
y=-2x+b
We plug in the values (5,2):
2=(-2)*5+b
2=-10+b
b=12
The equation is:
y=-2x+12
The study has the smallest margin of error for a 98% confidence interval is <span>The northern California study with a margin of error of 3.2%.
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F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
