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HACTEHA [7]
3 years ago
13

Five indicators of computer illiteracy​

Computers and Technology
1 answer:
melisa1 [442]3 years ago
8 0

1. Isn't fluent in "geek language"

2. Doesn't know how to use a web browser and it's features

3. Doesn't understand what a computer is and how it works

4. Doesn't know the basic parts of computer hardware

5. Doesn't know how to use a computer or any other electronics

You might be interested in
Do you agree to the song that ''magtanim ay di biro?'' why?
iren [92.7K]

Answer:

I agree in this song because being a farmer is not easy you need to be hardwork

5 0
2 years ago
Write a program that simulates a lottery. The program should havean array of five integers named lottery, and shouldgenerate a r
Fiesta28 [93]

Answer:

Here is the C++ program that simulates lottery:

#include<iostream>  //to use input output functions

using namespace std;  //to access objects cin cout

int main(){  //start of main function

int size= 5; // size of arrays

int range = 10;  //range of random numbers from 0 to 9

int user[size];  // user array

int lottery[size];  // lottery array

for(int i=0;i<size;i++)  //iterates through the array

lottery[i]=rand()%range;  // generates random number in specified range

cout<<"Enter "<<size<<" digits: ";  //prompts user to enter 5 digits

for(int i=0;i<size;i++)  //loops through the user array

cin>>user[i];  //reads input digits from user

int match=0;  //stores number of matching digits

for(int i=0;i<size;i++)  //iterates through array to compare user and lottery arrays

if(user[i]==lottery[i])  //if digit at i-th index of user array matches to that of lottery array

match++;  //increments count of matching digits by 1

cout<<"Lottery array: ";  // display digits of lottery array

for(int i=0;i<size;i++)  //iterates through elements of lottery array

cout<<lottery[i]<<" ";  //prints elements of lottery array with a space between them

cout<<endl;  //prints a new line

cout<<"  User  array: ";  // prints digits of user array

for(int i=0;i<size;i++) //iterates through elements of user array

cout<<user[i]<<" ";  //prints elements of user array

cout<<endl;  // prints a new line

if(match==size){  //if all the digits match

cout<<"Congratulations. You are a grand prize winner! "; }//displays this message proclaiming the user as a grand prize winner

else{  // if all digits of user array do not match with lottery array digits

cout<<"Number of digits matched: "<<match<<endl; //displays the number of matched digits

cout<<"Sorry! Better luck next time!" ;    //displays this message when all digits don't match

}

}    

Explanation:

If you want to keep the size and range fixed then you can use #define before the main() function to give a constant value to size and range as:

#define size 5

#define range 10

The program uses rand() function in order to generate random numbers for lottery array in the range of 0 through 9.

Then the program declares a user array with size = 5 and prompts user to enter 5 digits to stores in user array.

Next the program matches each digit of user array to the corresponding digit of lottery array and if the two digits match then the program increments the match variable by 1 to count the matched digits. For example, lets say lottery has the following elements:

lottery: 7,4,9,1,3

Lets say user array has following elements input by user at console

user: 4,2,9,7,3

Now at first iteration the digit 7 at 0-th index of lottery array is matched to the digit 4 at 0-th index of user array. This index is specified using variable i. These means the first element of lottery array is matched with first element of user array. As these digits are not equal so they don't match and the variable i is incremented to point to the position of next digit.

Now at second iteration the digit 4 in lottery array is matched to the digit 2 of user array. As these digits are not equal so they don't match and the variable i is incremented.

at third iteration the digit 9 in lottery array is matched to the digit 9 of user array. As these digits equal so they match and the variable match is incremented to 1 in order to count the number of matches. So value of match = 1

Now at fourth iteration the digit 1 in lottery array is matched to the digit 7 of user array. As these digits are not equal so they don't match and the variable i is incremented. The value of match also remains the same i.e. 1

at fifth iteration the digit 3 in lottery array is matched to the digit 3 of user array. As these digits equal so they match and the variable match is incremented to 1 in order to count the number of matches. So value of match = 2

Next the loop ends because the value of exceeds 5 which is the size of the array.

Next if(match==size) statement has an if condition which checks if all digits match. This is checked by comparing the count of match variable to the size of the array. The value of match is 2 and value of size is 5 so this means that all the digits do not match. Hence this condition evaluates to false. So the statement in if part will not execute and program moves to the statement: cout<<"Number of digits matched: "<<match<<endl; which displays the value of match variable i.e. 2 as:

Number of digits matched: 2

followed by statement cout<<"Sorry! Better luck next time!" ;  which displays the message:

Sorry! Better luck next time!

5 0
2 years ago
Which of the following is not possible? A class that implements two interfaces. A class that inherits from two classes. A class
ozzi

Answer:

"A class that inherits from two classes"

Explanation:

If we're talking about Java, you can't extend from two classes. The reason for this is Java doesn't allow multiple inheritance.

The reason for this is to avoid the ambiguity caused by it. One of the cases where multiple inheritance can cause ambiguity is the diamond problem.

Diamond problem can occur if two classes (say B and C) inherit from one class (say A). And another class (say D) inherits from both B & C.

If B and C class override the same method from A class. And D class calls that method, which one will be called, class B's or C's??

4 0
3 years ago
A group of statisticians at a local college has asked you to create a set of functions that compute the median and mode of a set
Vanyuwa [196]

Answer:

from functools import reduce

def mean(mylist):

   score = reduce(lambda x,y: x + y, mylist)/ len(mylist)

   return score

def median(mylist):

   sorted(mylist)

   list_len = len(mylist) % 2

   i = round(len(mylist)/2)

   x = len(mylist)//2

   if list_len == 0:

       median = (mylist[x] + mylist[x+1]) / 2  

   else:

       median = mylist[i]

   return median

def mode(mylist):

   unique = set(mylist)

   unique = list(unique)

   collector = [mylist.count(key) for key in unique]

   maxi = max(collector)

   loc = collector.index(maxi)

   return unique[loc]

def main():

   scores = input( 'Enter list of numbers: ').split(",")

   scores = [int(score) for score in scores]

   

   operation = input('Enter operation: ')

   operator = ['mean', 'median', 'mode']

   

   for x in iter(list, 0):

       if operation in operator:

           break

       print("Invalid operation: ")

       operation = input('Enter operation')

   

   index_loc = operator.index(operation)

   

   if index_loc == 0:

       return mean(scores)

   elif index_loc == 1:

       return median(scores)

       #return np.median(scores)  can be used of the defined function

   elif index_loc == 2:

       #return stats.mode(scores)[0]  can be used of the defined function

       return mode(scores)

print( main( ) )

Explanation:

The main python function calls conditionally three statistical functions namely mean, median and mode. It prompts for user input for a list of integer numbers and a function name name to return the corresponding result.

8 0
2 years ago
How can you use the Address Book to address an email message? Use the drop-down menus to complete the sentences. 1. Type an emai
Delvig [45]

Answer:

1. AutoCorrect

2. Address book

Explanation:

stan bts ?

5 0
3 years ago
Read 2 more answers
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