The area of a dog pen is 14 1/5 square feet. The length of the pen is 8 ½ feet. What is the width?

Mathematics

1 answer:

Katen [24]3 years ago

5 0

Answer:

The width is 1.67 or 1 2/3 feet approximately

Step-by-step explanation:

Area of the dog pen = 14 1/5 = 14.2 square feet

Length of the pen = 8 1/2 = 8.5 feet

Width of the pen = x

Let's recall that the formula of the area of a rectangle is:

Area = Length * Width

Replacing with the values we know:

14 1/5 = 8 1/2 * Width

14.2 = 8.5 * Width

Width = 14.2/8.5

Width = 1.67 feet (rounding to the next hundredth)

1.67 ≅ 1 2/3

The width is 1.67 or 1 2/3 feet approximately

You might be interested in

Evaluate the definite integral using the graph of f(x) (Image included)

Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

$\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}$

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

$\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}$