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ioda
3 years ago
12

Imitates the function, behavior or process of the thing it represents

Mathematics
1 answer:
Sav [38]3 years ago
4 0
It represents simulations
You might be interested in
1.) Multiply 2ab(−a+2b+3).(1 point)
GarryVolchara [31]

Answer:

(x+3)(4x−2)  =  4x2+10x−6

(x+2)(x2−3x +4) = x3−x2−2x+8

Step-by-step explanation:

8 0
3 years ago
Let Y1 and Y2 have the joint probability density function given by:
Ann [662]

Answer:

a) k=6

b) P(Y1 ≤ 3/4, Y2 ≥ 1/2) =  9/16

Step-by-step explanation:

a) if

f (y1, y2) = k(1 − y2), 0 ≤ y1 ≤ y2 ≤ 1,  0, elsewhere

for f to be a probability density function , has to comply with the requirement that the sum of the probability of all the posible states is 1 , then

P(all possible values) = ∫∫f (y1, y2) dy1*dy2 = 1

then integrated between

y1 ≤ y2 ≤ 1 and 0 ≤ y1 ≤ 1

∫∫f (y1, y2) dy1*dy2 =  ∫∫k(1 − y2) dy1*dy2 = k  ∫ [(1-1²/2)- (y1-y1²/2)] dy1 = k  ∫ (1/2-y1+y1²/2) dy1) = k[ (1/2* 1 - 1²/2 +1/2*1³/3)-  (1/2* 0 - 0²/2 +1/2*0³/3)] = k*(1/6)

then

k/6 = 1 → k=6

b)

P(Y1 ≤ 3/4, Y2 ≥ 1/2) = P (0 ≤Y1 ≤ 3/4, 1/2 ≤Y2 ≤ 1) = p

then

p = ∫∫f (y1, y2) dy1*dy2 = 6*∫∫(1 − y2) dy1*dy2 = 6*∫(1 − y2) *dy2 ∫dy1 =

6*[(1-1²/2)-((1/2) - (1/2)²/2)]*[3/4-0] = 6*(1/8)*(3/4)=  9/16

therefore

P(Y1 ≤ 3/4, Y2 ≥ 1/2) =  9/16

8 0
3 years ago
You're really good at investing
o-na [289]

Answer:

What do you mean by "You are really good at investing" ?

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
How to solve 1/2-4=7 in 2 steps​
Ad libitum [116K]

Answer:

Step-by-step explanation:

-7/2

Decimal form:

-3.5

Mixed fraction:

-3 1/2

Continued fraction:

- [3; 2]

Egyptian fraction expansion:

-4 + 1/2

6 0
2 years ago
As voters exit the polls, you ask a representative random sample of voters if they voted for a proposition. If the true percenta
tresset_1 [31]

Answer:

The probability is 0.057797

Step-by-step explanation:

Consider the provided information.

It is given that true percentage of voters who vote for the proposition is 63%,

Let p is probability of success.

According to the binomial distribution:

P(x;p,n)=^nC_x(p)^x(1-p)^{(n-x)}

Substitute n=7, p=0.63 and x=2 in the above formula.

P(x;p,n)=^7C_2(0.63)^2(1-0.63)^{(7-2)}

P(x;p,n)=\frac{7!}{2!5!}(0.3969)(0.37)^{5}\\P(x;p,n)=21(0.3969)(0.37)^{5}\\P(x;p,n)=0.0577974947199\\P(x;p,n)\approx0.057797

Hence, the probability is 0.057797

8 0
3 years ago
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