Answer: The isotopic abundance of Cl- 37 is 0.2424.
Explanation:
Mass of isotope - 35 = 34.96885 amu
% abundance of isotope -35= x% =
Mass of isotope - 37 = 36.9659 amu.
% abundance of isotope-37 = (100-x)% =
Formula used for average atomic mass of an element :
Therefore, the isotopic abundance of Cl- 37 is 0.2424.
Answer:
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Explanation:
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Answer:
Density=2kg/6m^3=1/3 kg/m^3
Explanation:
The average that reflect the typical ratio of natural abundance of iron isotope is the atomic weight of the iron. Iron has four stable isotope that is iron 54 ,56, 57, 58. its atomic weight by mass is 9.27 x10^-22 grams
therefore number of atoms in cm^3 is
(7.87g/cm^3)/(9.27x10^-22)=8.49x10^21atoms/cm^3