Answer:
1600
Explanation:
5×10^4÷2.5×10^2
(5×10^4)
(10^4)
(5×40)
(200)
(200÷2.5)
(80)
(80×10^2)
(10^2)
(20)
(80×20)
Answer is 1600.
Sorry if it's not correct.
Answer:
0.057 M
Explanation:
Step 1: Given data
Solubility product constant (Ksp) for HgBr₂: 2.8 × 10⁻⁴
Concentration of mercury (II) ion: 0.085 M
Step 2: Write the reaction for the solution of HgBr₂
HgBr₂(s) ⇄ Hg²⁺(aq) + 2 Br⁻
Step 3: Calculate the bromide concentration needed for a precipitate to occur
The Ksp is:
Ksp = 2.8 × 10⁻⁴ = [Hg²⁺] × [Br⁻]²
[Br⁻] = √(2.8 × 10⁻⁴/0.085) = 0.057 M
Answer:
b
Explanation:
A pure substance has a constant composition and cannot be separated into simpler substances by physical means. There are two types of pure substances: elements and compounds.
Answer:
reproduction
Explanation:
reproduction, process by which organisms replicate themselves
