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Sonbull [250]
3 years ago
10

Which one goes where? Thanks! It's in a file. ⬇

Chemistry
2 answers:
nordsb [41]3 years ago
5 0

ANSWER:

oh my this is my first time answering a question like this:

siniylev [52]3 years ago
5 0

1 -> theory

2-> law

3->  hypothesis

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An earthquake on the ocean floor produced a giant wave called a tsunami. The tsunami traveled through the ocean and hit a remote
Svetlanka [38]

Answer:

Yes

Explanation:

What cause an earthquake is when the earth plates shift and if theirs a drop in the tentonic plates a ripple effect like when you drop something in water will occur. The plates shift down the water in which the plate shift down the water will go in that direction due to gravity, but instead of equalizing the water will pick up some speed and velocity and begin to form a wave now. When an tsunami happens you know it coming cause the water moves back cause the water is picking up to much speed and due to cohesion its moves along with the move water and builds up. Creating a massive tidal wave known as tsunamis.

8 0
4 years ago
C12H22O11 is an example of a(n):
ycow [4]

Answer:

molecular compound

Explanation:

it has two or more nonmetal elements and are covalently bonded

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3 years ago
A roller coaster track is 3,000 meters long. It takes 100 seconds totravel once around the roller coaster. What is the average s
postnew [5]
The rollercoaster went 200 miles.
3 0
3 years ago
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The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3×10−5. Calculate the equilibrium concentration of H3O+ in the s
raketka [301]

Answer : The equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

Explanation :

The dissociation of acid reaction is:

                       C_6H_5COOH+H_2O\rightarrow H_3O^++C_6H_5COO^-

Initial conc.        c                                 0                0

At eqm.             c-x                                 x                x

Given:

c = 7.0\times 10^{-2}M

K_a=6.3\times 10^{-5}

The expression of dissociation constant of acid is:

K_a=\frac{[H_3O^+][C_6H_5COO^-]}{[C_6H_5COOH]}

K_a=\frac{(x)\times (x)}{(c-x)}

Now put all the given values in this expression, we get:

6.3\times 10^{-5}=\frac{(x)\times (x)}{[(7.0\times 10^{-2})-x]}

x=2.1\times 10^{-3}M

Thus, the equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

4 0
3 years ago
20.00 mL of a 0.077 M solution of silver nitrate, AgNO3
melomori [17]
N= m/v n=0.077/.200 = 0.385
8 0
3 years ago
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