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arsen [322]
3 years ago
14

What is the most compressible at room temperature

Chemistry
1 answer:
german3 years ago
5 0

Gas is the most compressible at room temperature.

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Calculate the volume in mL of 1 mole of pure ethanol
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The units of density are g/ml. If you find the grams of 1 mol of ethanol (with the molecular weight), you can then divide by the density to get the ml of ethanol.

g*(ml/g)=ml
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What two elements are used to make a laser pen light?
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Helium and Neon

Explanation:

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What is an acid meaning?
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A glucose solution is administered intravenously into the bloodstream at a constant rate r. As the glucose is added, it is conve
Helen [10]

Answer:

C(t)=\frac{r}{k}-(\frac{r-kC_o}{k})e^{-kt}

Explanation:

The differential equation is given as:

\frac{dC}{dt} = r- kC

\frac{dC}{r- kC} = dt

Taking integral of both sides; we have:

\int\limits  \frac{dC}{r- kC} = \int\limits dt

-\frac{1}{k} In(r-kC) = t+D\\In(r-kC)=-kt-kD

r-kC=e^{-kt-kD}

r-kC=e^{-kt}e^{-kD}

r-kC=Ae^{-kt}

kC=r-Ae^{-kt}

C=\frac{r}{k}-\frac{A}{k}e^{-kt}

C(t)=\frac{r}{k}-\frac{A}{k}e^{-kt}     ------- equation (1)

If C(0)= C_o ; we have:

C(0)= \frac{r}{k}-\frac{A}{k}e^0         (where; A is an integration constant)

C_o = \frac{r}{k}- \frac{A}{k}

C_o=\frac{r-A}{k}

kC_o=r-A

A=r-kC_o

Substituting A=r-kC_o into equation (1); we have;

C(t)=\frac{r}{k}-(\frac{r-kC_o}{k})e^{-kt}

3 0
4 years ago
before the quarry was dug, the land contained more vegetation . what impact has this change most likely had on the local ecosyst
Sergio039 [100]
It was loss of nutrients, I think


Explanation:

The quarry was dug up and vegetation started dying. The quarry was probably rich with nutrients

Please brainliest !! ❤️
5 0
3 years ago
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