B is the answer to ur question
Answer:
P = 12m
A = 6m^2
Step-by-step explanation:
Perimeter is the sum of all the lengths of a shape. The lengths of the triangle are given as 3m, 4m, and 5m, so to find the perimeter we just need to add them all together. 3+4+5=12, so the perimeter of the triangle is 12m.
The area of a triangle is found by multiplying its height by its base and then dividing the result by 2. The height of the triangle is not given, but the side lengths (3,4 and 5) indicate that the triangle is a right triangle. This means we can use the middle length as the height and the shortest length as the base.
So, the height of the triangle is 4m, and the base is 3m, so to calculate the area:
(3x4)/2=12/2=6m^2.
The area of the triangle is 6m^2.
Hope this helped!
Polynomials are expressions whose exponents are non-negative integers and the coefficients are real numbers. The leading term is the term with the highest power. The coefficient of the leading term is the leading coefficient. The power of x in the leading term is called the degree of the polynomial! Here are some examples of polynomials:
Degree Name Example
0 constant 11
1 linear 4x + 7
2 quadratic 3x2 + 4x + 5
3 cubic 4x3 + 3x + 7
4 quartic 3x4 + 2x2 + 4
5 quintic x5 + 3x + 1
Any value of x such that P(x) = 0 is a root of the equation and a zero of the function.
Review of synthetic substitution
To use synthetic substitution, do the following:
1) Write the polynomial in descending order.
2) Make sure any missing terms are replaced with zero!
3) Bring down the leading coefficient.
4) Multiply by the divisor and add to the next term.
5) Repeat the process until the last coefficient is reached.
Example
Use synthetic division to find P(2) for P(x) = 2x3 - 9x2 + 27
2| 2 -9 0 27
4 -10 -20
2 -5 -10 7 The value of P(2) = 7, the last number!!
Sample Problems
1) State whether each is a polynomial function. If yes, find the degree and the zeros.
Problem Polynomial? Degree zeros
a) f(x) = 5 - 4x yes 1 5/4
b) f(x) = 3x2 - 6x yes 2 0, 2
c) f(x) = x - 3/x no
d) f(x) = 18 yes 0 none
e) f(x) = (x-3)/(x+2) no
2) Use synthetic substitution to find P(3) for each function:
a) P(x) = 4x3 - 5x2 + 3
3| 4 -5 0 3
12 21 63
4 7 21 66
Therefore, P(3) = 66
b) P(x) = 3x4 + 2x3 - 5x - 2
3| 3 2 0 -5 -2
9 33 99 282
3 11 33 94 280
Therefore, P(3) = 280
3) If 4 is a zero of f(x) = 3x3 + kx - 2, find the value of k.
Since 4 is a zero, the value of f(4) = 0. Use synthetic substitution.
4| 3 0 k -2
12 48 192 + 4k
3 12 48 + k 190 + 4k
Now 190 + 4k = 0, solve for k
4k = -190
k = -190/4 = -47.5
Answer:
(x-1)(x-1)
Step-by-step explanation:
hello :
(x+2) ²-6 (x+ 2) +9 =(x+2) ²-2×(<em>3</em>) (x+ 2) +<em>3²</em>
by identity : (a-b)² = a²-2ab+b²
let : a=x+2 and b= <em>3</em>
(x+2) ²-6 (x+ 2) +9 =(x+2) ²-2×(<em>3</em>) (x+ 2) +<em>3²=</em> ((<em>x+2)-3</em>)<em>²= (</em>x+2-3)² = (x-1)²=
(x-1)(x-1)
The answer is c. 72cm^2
for each section of the prism you multiply the length times the width and then add all of the numbers together to get 72
