Answer:
Step-by-step explanation:
Comment
The first step is to find the surface area of 1 fence post.
The formula is
Area_ends = 2 pi r^2 for the ends.
Area_body = 2*pi*r * h
Givens
r = d/2 r is the radius ; d is the diameter
r = 1/2 foot
h = 10 feet
Solution
1 fence post
Area = ends + area body
Area = 2*3.14 * (1/2)^2 + 2 * pi * r * h
Area = 2*3.14* (1/2)^2 + 2 * 3.14 * 1/2 * 10
Area = 1.57 + 31.4
Area = 32,97 square feet.
10 fence posts
10*32.97 = 329.7 square feet
Answer
10 fence posts have 329.7 square feet in area.
100035 because the numbers are all even and i am in first grade so yeah
Answer:
D
Step-by-step explanation:
The hypotenuse squared is equal to the sum of the legs squared in a right triangle.
∴ c² = a² + b² (Pythagorean’s Theorem)
c² = 3.4² + 6.7² (substitute the given values for a & b)
c² = 11.56 + 44.89 (square both right hand terms)
c² = 56.45 (add the right hand side values)
c = √56.45 (square root of both sides)
c ≈ 7.5 to the nearest tenth QED
The two lines in this system of equations are parallel
Step-by-step explanation:
Let us revise the relation between 2 lines
- If the system of linear equations has one solution, then the two line are intersected
- If the system of linear equations has no solution, then the two line are parallel
- If the system of linear equations has many solutions, then the two line are coincide (over each other)
∵ The system of equation is
3x - 6y = -12 ⇒ (1)
x - 2y = 10 ⇒ (2)
To solve the system using the substitution method, find x in terms of y in equation (2)
∵ x - 2y = 10
- Add 2y to both sides
∴ x = 2y + 10 ⇒ (3)
Substitute x in equation (1) by equation (3)
∵ 3(2y + 10) - 6y = -12
- Simplify the left hand side
∴ 6y + 30 - 6y = -12
- Add like terms in the left hand side
∴ 30 = -12
∴ The left hand side ≠ the right hand side
∴ There is no solution for the system of equations
∴ The system of equations represents two parallel lines
The two lines in this system of equations are parallel
Learn more:
You can learn more about the equations of parallel lines in brainly.com/question/8628615
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Answer:
√(p²-4q)
Step-by-step explanation:
Using the Quadratic Formula, we can say that
x = ( -p ± √(p²-4(1)(q))) / 2(1) with the 1 representing the coefficient of x². Simplifying, we get
x = ( -p ± √(p²-4q)) / 2
The roots of the function are therefore at
x = ( -p + √(p²-4q)) / 2 and x = ( -p - √(p²-4q)) / 2. The difference of the roots is thus
( -p + √(p²-4q)) / 2 - ( ( -p - √(p²-4q)) / 2)
= 0 + 2 √(p²-4q)/2
= √(p²-4q)
