Answer:
E₂ = 3ax +4ay + 2az
Interface angles ∅₁ = 45°
∅₂ = 68.20°
Explanation:
See the attached files for the calculation
The plates push apart from eachother
Answer:
C. The forces are balanced.
Explanation:
Every answer other than C means the object moved.
Answer:
a. ![Area=144cm^{2}](https://tex.z-dn.net/?f=Area%3D144cm%5E%7B2%7D)
b. decrease
c. 43.5psi
Explanation:
Answer:
a. ![Area=144cm^{2}](https://tex.z-dn.net/?f=Area%3D144cm%5E%7B2%7D)
Explanation:
from the questions, the car has four tires which support the weight equally.we can conclude that the weight support by each tire is
weight support of each tire =1420/4=355kg.
a. since ![pressure=\frac{force}{area}](https://tex.z-dn.net/?f=pressure%3D%5Cfrac%7Bforce%7D%7Barea%7D)
we need to determine the force, ![F=mg\\](https://tex.z-dn.net/?f=F%3Dmg%5C%5C)
the "g" is the acceleration due to gravity which has a constant value of ![9.8m/s^{2}](https://tex.z-dn.net/?f=9.8m%2Fs%5E%7B2%7D)
hence the force on each tire is
![F=mg\\F=355*9.8\\F=3479N\\](https://tex.z-dn.net/?f=F%3Dmg%5C%5CF%3D355%2A9.8%5C%5CF%3D3479N%5C%5C)
Also, since the pressure is giving in psi, we have to convert it to pascal
since 1psi=6895pascal
hence 35psi to pascal is
.
From the expression for pressure
![pressure =\frac{force}{area}\\](https://tex.z-dn.net/?f=pressure%20%3D%5Cfrac%7Bforce%7D%7Barea%7D%5C%5C)
we have
![Area=\frac{force}{area}\\\\ Area=\frac{3479}{241325} \\Arae=0.0144\\](https://tex.z-dn.net/?f=Area%3D%5Cfrac%7Bforce%7D%7Barea%7D%5C%5C%5C%5C%20Area%3D%5Cfrac%7B3479%7D%7B241325%7D%20%5C%5CArae%3D0.0144%5C%5C)
to cm
we multiply by
![Area=144cm^{2}](https://tex.z-dn.net/?f=Area%3D144cm%5E%7B2%7D)
b. The effect of the pressure can be determine from the relationship between the pressure and the area using the pressure formula
![p=\frac{force}{area} \\p\alpha \frac{1}{A}\\](https://tex.z-dn.net/?f=p%3D%5Cfrac%7Bforce%7D%7Barea%7D%20%5C%5Cp%5Calpha%20%5Cfrac%7B1%7D%7BA%7D%5C%5C)
hence an increase in the pressure will lead to a decrease in the contact Area
C. if the area ia now
converting to meter square
![116/10^{4} \\Area=0.0116m^{2} \\](https://tex.z-dn.net/?f=116%2F10%5E%7B4%7D%20%5C%5CArea%3D0.0116m%5E%7B2%7D%20%5C%5C)
the pressure now is
converting to psi we have
Hi there!
We can use impulse for this situation:
I = Δp = mΔv
Impulse = Force × time, so:
I = 63.9(24) = 1533.6 Ns
Find force by dividing by time:
I/t = 1533.6/1.2 = 1278 N