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Lena [83]
2 years ago
7

Why do you think spacecraft that carry instruments to collect data about objects in space are called probes?

Physics
2 answers:
lana66690 [7]2 years ago
7 0

Answer:

so whats the answer i really need this please

Explanation:

yarga [219]2 years ago
3 0

Answer:

my mind cant comprehend a shing word u just said

Explanation:

You might be interested in
PLEASE HELP!!! URGENTTT
Ludmilka [50]

Answer:

For the first one, its "attract"

4 0
2 years ago
Why is the meteor shower is best observed after midnight?​
harkovskaia [24]

Answer:

At dawn your location on earth is pointed straight in the direction of the Earth's travel in its orbit.  Between midnight and dawn you are moving head-on through the location of the meteors in space, which means that you will, on average, observe more of them.

- public.nrao.edu

Explanation:

hope this helps

4 0
3 years ago
g The magnetic force on a charged particle A. depends on the sign of the charge on the particle. B. depends on the velocity of t
Leona [35]

Answer:

E) is described by all of these

Explanation:

The magnetic force on a charged particle is expressed as:

F = qv * B = qvBsinθ

Where,

q = charge on particle

θ = angle between the magnetic field and the particle velocity.

v = velocity of the particle

B = magnitude of field vector

From here, we could denote that magnetic force, F depends on charge on particle, velocity of particle, magnitude of field vector.

The magnetic force on a charged particle is at right angles to both the velocity of the particle. The magnetic force and magnetic field in a charged particle are perpendicular to each other, the right hand rule is used to determine the direction of force.

The correct option is E.

3 0
2 years ago
Read 2 more answers
¿Cuál es la magnitud y dirección de la aceleración de los cuerpos en caída libre en el planeta Tierra?
Tatiana [17]

La magnitud es de 9.8 m/s² ... la aceleración de la gravedad en o cerca de la superficie de la Tierra.

La dirección es hacia el centro de la Tierra. (Llamamos a esa dirección "abajo").

6 0
3 years ago
Our eyes are typically 6 cm apart. Suppose you are somewhat unique, and yours are 9.50 cm apart. You see an object jump from sid
Serhud [2]

Answer: 12.67 cm, 8 cm

Explanation:

Given

Normal distance of separation of eyes, d(n) = 6 cm

Distance of separation is your eyes, d(y) = 9.5 cm

Angle created during the jump, θ = 0.75°

To solve this, we use the formula,

θ = d/r, where

θ = angle created during the jump

d = separation between the eyes

r = distance from the object

θ = d/r

0.75 = 9.5 / r

r = 9.5 / 0.75

r = 12.67 cm

θ = d/r

0.75 = 6 / r

r = 6 / 0.75

r = 8 cm

Thus, the object is 12.67 cm far away in your own "unique" eyes, and just 8 cm further away to the normal person eye

8 0
3 years ago
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