If each edge of a square increased by 50%, by what percentage does the a?rea increase

Fill in the missing expression

padilas [110]

Answer:

The complete table is:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ -a ] = [ 2b + 4 ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ 7a + 2b ] + [ 3a + 8 ] + [ 0 ] = [10a + 2b + 8 ]

Explanation:

You can determine the content of each box by subtraction, running the rows and the columns.

The expressions are:

[ 5a ] + [ ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ ] = [ ]

+ + + +

[ ] + [ ] + [ -3a ] = [ 1 ]

= = = =

[ ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

1. First row:

[ 5a ] + [ ] + [ 4a ] = [ 10a + 3 ]

[ ] = [10a+ 3] - [ 4a ] - [ 5a ] = 10a - 4a - 5a + 3 = a + 3

2. Second colum:

[ a + 3 ] + [ 4 + a ] + [ ] = [ 3a + 8 ]

[ ] = [ 3a + 8 ] - [ a + 3 ] - [ 4 + a ] = 3a - a + a + 8 - 4 - 3 = a + 1

So far, you have completed this:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ ] = [ ]

+ + + +

[ ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

3. Complete the row 3:

[ ] + [ a + 1 ] + [ -3a ] = [ 1 ]

[ ] = [ 1 ] - [ a + 1 ] - [ -3a ] = - a + 3a + 1 - 1 = 2a

So far, you have completed this:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ ] = [ ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

4. Complete the fourth column:

[ 10a + 3 ] + [ ] + [ 1 ] = [10a + 2b + 8 ]

[ ] = 10a + 2b + 8 - 10a - 3 - 1 = 2b + 4

So far, this is the results:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ ] = [ 2b + 4 ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

5. Complete the second row:

[ 2b ] + [ 4 + a ] + [ ] = [ 2b + 4 ]

[ ] = [ 2b + 4 ] - [ 2b ] - [ 4 + a ] = 2b - 2b + 4 - 4 - a = - a

So far:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ -a ] = [ 2b + 4 ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

6. Complete the first colum:

[ 5a ] + [ 2b ] + [2a ] = [ ]

[ ] = [ 7a + 2b ]

So far:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ -a ] = [ 2b + 4 ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ 7a + 2b ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

7. Complete the last row:

[ 7a + 2b ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

[ ] = [10a + 2b + 8 ] - [ 7a + 2b ] - [ 3a + 8 ] = 0

The complete table is:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ -a ] = [ 2b + 4 ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ 7a + 2b ] + [ 3a + 8 ] + [ 0 ] = [10a + 2b + 8 ]

5 0

3 years ago

Solve the equation 12x-14=4x+10

ziro4ka [17]

Answer:

x=3

Step-by-step explanation:

12x-14=4x+10

Subtract 4x from each side

12x-4x-14=4x-4x+10

8x - 14 = 10

Add 14 to each side

8x - 14+14 = 10+14

8x = 24

Divide each side by 8

8x/8 = 24/8

x = 3

3 0

2 years ago

Read 2 more answers

NEED HELP ASAP!!!! WILL MARK BRAINLIEST!!!!

viva [34]

Answer:

20

Step-by-step explanation:

3 0

2 years ago

)

Leto [7]

Answer:

Number of Adult's tickets sold on Saturday = 3,356

Number of Children's tickets sold on Saturday = 2, 928

Total number of tickets sold over these two days is 8,938.

Step-by-step explanation:

Here, the number of tickets sold on FRIDAY:

Adult Ticket sold = 1,678

Children's Tickets sold = 976

So, the total number of tickets sold on Friday

= Sum of ( Adult + Children's ) tickets = 1,678 + 976 = 2,654 .... (1)

The number of tickets sold on SATURDAY:

Adult Ticket sold = 2 times the number of adult tickets sold on Friday

= 1,678 x 2 = 3,356

Children's Tickets sold = 3 times the number of children's tickets sold on Friday.

= 976 x 3 = 2, 928

So, the total number of tickets sold on Saturday

= Sum of ( Adult + Children's ) tickets = 3,356 + 2,928 = 6, 284 .... (2)

Now, the total number of tickets booked in these two days :

Sum of tickets booked on (Friday + Saturday)

= 2,654 + 6, 284 = 8,938

Hence, total number of tickets sold over these two days is 8,938.

6 0

2 years ago

For the love of God help me !! I'm desperate for it tomorrow

Eduardwww [97]

Try to relax. Your desperation has surely progressed to the point where
you're unable to think clearly, and to agonize over it any further would only
cause you more pain and frustration.
I've never seen this kind of problem before. But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.

Consider this: (2)^a negative power = (1/2)^the same power but positive.

So:
Whatever power (2) must be raised to, in order to reach some number 'N',
the same number 'N' can be reached by raising (1/2) to the same power
but negative.

What I just said in that paragraph was: log₂ of(N) = - log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.

Now let's look at the problem:

log₂(x-1) + log(base 1/2) (x-2) = log₂(x)

Subtract log₂(x) from each side:

log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0

Subtract log(base 1/2) (x-2) from each side:

log₂(x-1) - log₂(x) = - log(base 1/2) (x-2) Notice the negative on the right.

The left side is the same as log₂[ (x-1)/x ]

==> The right side is the same as +log₂(x-2)

Now you have: log₂[ (x-1)/x ] = +log₂(x-2)

And that ugly [ log to the base of 1/2 ] is gone.

Take the antilog of each side:

(x-1)/x = x-2

Multiply each side by 'x' : x - 1 = x² - 2x

Subtract (x-1) from each side:

x² - 2x - (x-1) = 0

x² - 3x + 1 = 0

Using the quadratic equation, the solutions to that are
x = 2.618
and
x = 0.382 .

I think you have to say that x=2.618 is the solution to the original
log problem, and 0.382 has to be discarded, because there's an
(x-2) in the original problem, and (0.382 - 2) is negative, and
there's no such thing as the log of a negative number.

There,now. Doesn't that feel better.

4 0

2 years ago