Find the radius of the circle that has an area of 200.96cm^2

Which situation could be represented by the graph?

Ymorist [56]

The correct option which resembles with the given graph is $\fbox{\begin\\\ optionA and optionC\\\end{minispace}}$ .

Further explanation:

From the given graph the it is observed that the interval is $[8,11)$ which is a half open interval or it can be said that it is a half closed interval.

A half closed or a half open interval is an interval in which one end point of the interval is included but the other point is not included.

For example:

In an interval of the form $[a,b)$ the point $a$ is included in the set but the point $b$ is not included in the set.

Similarly, in the interval $[8,11)$ the point $8$ is included in the set but the point $11$ is not included in the set.

In order to determine the correct option which resembles with given graph form interval for each option.

Option A:

As per the statement in option A the age of the student must be at least $8$ years and not more than $11$ years that is the age of the student is either $8$ years or greater than $8$ years and less than $11$ years.

As per the above statement the interval formed is $\fbox{\begin\\\ [8,11)\\\end{minispace}}$ in which $8$ is included in the set and $11$ is not included which means it is a half closed or half opoen interval.

Therefore, $\fbox{\begin\\\ optionA\\\end{minispace}}$ is a correct option.

Option B:

As per the statement in option B the amount of money the babysitter can earn is between $\$8$ and $\$11$ per hour.

As per the above statement the interval formed is $\fbox{\begin\\\ (8,11)\\\end{minispace}}$ in which both of the end points are not included in the set which means that it is an open interval.

Therefore, $\fbox{\begin\\\ optionB\\\end{minispace}}$ is an incorrect option.

Option C:

As per the statement in option C the time required to complete a program in college cannot be less than $8$ hours and the time must be less than $11$ hours.

From the above statement it is concluded that the time required can be $8$ hours or more than $8$ hours but it has to be less than $11$ hours.

So, as per the above the statement the interval formed is $\fbox{\begin\\\ [8,11)\\\end{minispace}}$ .

Therefore, $\fbox{\begin\\\ optionC\\\end{minispace}}$ is a correct option.

Option D:

As per the statement in option D the age of the dogs is either $8$ years old or below $8$ years and age of the dog must be greater than $11$ tears.

As per the above statement the interval formed is $\fbox{\begin\\\ (-\infty,8) \bigcup(11,\infty)\\\end{minispace}}$ .

Therefore, the $\fbox{\begin\\\ optionD\\\end{minispace}}$ is an incorrect option.

So, $\fbox{\begin\\\ optionA and optionC\\\end{minispace}}$ are the correct options which resembles with the given graph.

Learn more:

A problem on composite function brainly.com/question/2723982
A problem to find radius and center of circle brainly.com/question/9510228
A problem to determine intercepts of a line brainly.com/question/1332667

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Sets

Keywords: Interval, set, open interval, closed interval, half open interval, half closed interval, set theory, program, community college, babysitters, veterinary clinic, ages, students.

5 0

3 years ago

Read 2 more answers

How do i find the are and perimeter of the composite figure?

sineoko [7]

Answer:

perimeter :

4+10+4+ (pi * radius) .........."radius =5"

area:

(10*4)+(0.5 * pi * r square)

7 0

3 years ago

What issue did the great compromise resolve

kondor19780726 [428]

Answer:

The issue of the great compromise resolved representation.

Step-by-step explanation:

8 0

3 years ago

PLS HELP!! WILL MAKE BRAINLIEST!!!!

poizon [28]

Answer:

(86.2,0) is the x-intercept.

Step-by-step explanation:

You can use the slope formula to figure this one out:

Just use two of the points on the table, any of them will work:

$(33,-22)\\(52,-33)$

$\frac{-22-33}{33-52} =\frac{-55}{-19}=\frac{55}{19}$

Now you have the slope of the equation, now using the y-intercept equation you can substitute the variables for point of the table and the new slope.:

$(71,-44)\\y=mx+b\\-44=\frac{55}{19} (71)+b$

Now just solve for b to get the y intercept:

$-44=\frac{55}{19}(71)+b\\-44= \frac{3905}{19} +b\\(-\frac{3905}{19})-44=\frac{3905}{19} +b(-\frac{3905}{19})\\ -\frac{4741}{19}=b$

Now you have the y-intercept so you just have to plug in 0 to the y spot and it will calculate the x-intercept.

$0=\frac{55}{19}x-\frac{4741}{19}\\(+\frac{4741}{19})0=\frac{55}{19}x-\frac{4741}{19}(+\frac{4741}{19})\\\\\frac{4741}{19}=\frac{55}{19}x\\\frac{\frac{4741}{19}}{\frac{55}{19} }= \frac{\frac{55}{19} x}{\frac{55}{19} } \\\frac{431}{5} =x\\or\\86.2=x$

And that's the x-intercept.

5 0

2 years ago

Read 2 more answers

Answer the question present in the picture

never [62]

The solution step by step. 43 comes from adding all the given numbers together.

7 0

3 years ago