All categories

3 years ago

Hamid has gained weight. He now weighs 88kg, which is 10% higher than his normal weight. What is his normal weigh?

Mathematics

2 answers:

kozerog [31]3 years ago

8 0

Answer:

80kg

Step-by-step explanation:

100 + 10 = 110% (Percentage of gained weight)

110% = 88000

1% = 88000 ÷ 110 = 800

100% = 800 x 100 = 80000

Dimas [21]3 years ago

7 0

Answer:

80kg

Step-by-step explanation:

let the normal weight be Y

88 = 10% of Y + Y

88 = 10/100 x Y + Y

88 = 0.1Y + Y

88 = 1.1Y

Divide both sides by 1.1

88/1.1 = 1.1Y/1.1

80 = Y

You might be interested in

What is the midpoint of the vertical line segment graphed below? (2, 4), (2, -9) A. (4, -5). B. (2, -5/2). C. (2, -5). D. (4, 5/

omeli [17]

Answer:

B. $(2, -\frac{5}{2})$

Step-by-step explanation:

Given:

(2, 4) and (2, -9)

Required:

Midpoint of the vertical line with the above endpoints

Solution:

Apply the midpoint formula, which is:

$M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$

Where,

(2, 4) = (x_1, y_1)

(2, -9) = (x_2, y_2)

Plug in the values into the equation:

$M(\frac{2 + 2}{2}, \frac{4 + (-9)}{2})$

$M(\frac{4}{2}, \frac{-5}{2})$

$M(2, -\frac{5}{2})$

8 0

2 years ago

Help please <br><br> marking brainlist

luda_lava [24]

I can help you but i cant see with the reflection thingy

4 0

2 years ago

Can I get the answers for number 14 plz?

nataly862011 [7]

A.
-1:
$2(2)^{-1} \\ 2( \frac{1}{2}) \\ \frac{2}{2} \\ 1$
(-1,1)

0:
$2(2)^{0} \\ 2(1) \\ 2$
(0, 2)

1:
$2(2)^{1} \\ 2(2) \\ 4$
(1, 4)

2:
$2(2)^{2} \\ 2(4) \\ 8$
(2, 8)

3:
$2(2) ^{3} \\ 2(8) \\ 16$
(3,16)

b.
To graph the equation, simply go through the points (-2, 0.5), (-1, 1), (0,2), (1,4), (2,8), and (3,16). Make sure you never go below 0 on the x-axis, because there's an asymptote there.

Hope this helps!

8 0

2 years ago

Read 2 more answers

A line goes through the point (-8,9), and has a slope of 3/4

olya-2409 [2.1K]

Answer:

$y=\dfrac{3}{4}x+15$