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Gemiola [76]
3 years ago
12

ABCD∼EFGH

Mathematics
2 answers:
Papessa [141]3 years ago
8 0
Hmph.. This one is kinda tricky, I believe it's 7.85..
Misha Larkins [42]3 years ago
8 0

Answer: The measure of FG = 20 inches.

Step-by-step explanation:

Since we have given that

ABCD~ EFGH

where, AD = 45 in.

EH = 60 in.

BC = 15 in.

We need to find the measure of FG.

Since the quadrilateral ABCD is similar to EFGH, then the ratio of their corresponding sides will be equal.

So, it becomes,

\frac{AD}{EH}=\frac{BC}{FG}\\\\\frac{45}{60}=\frac{15}{FG}\\\\\frac{3}{4}=\frac{15}{FG}\\\\FG=\frac{15\times 4}{3}=5\times 4=20\ in.

Hence, the measure of FG = 20 inches.

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✍<u> </u><u>F</u><u>o</u><u>r</u><u> </u><u>s</u><u>l</u><u>o</u><u>p</u><u>e</u><u>,</u><u> </u><u>m</u><u> </u>:

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✍<u> </u><u>For</u><u> </u><u>y-intercept</u><u>,</u><u> </u><u>c</u><u> </u>:

{ \tt{y = mx + c}}

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{ \boxed{ \tt{y =  - 7x + 5}}}

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