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3 years ago

What is the difference between the median and the range in the data set shown below?

Mathematics

1 answer:

Rina8888 [55]3 years ago

5 0

Answer:

a. 5

Step-by-step explanation:

arrange

1 2 3 5 5 6 6 6 8 9 9 10 10 11 12 13

median=6+8/2=7

range=13-1=12

difference=12-7=5

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EMERGENCY (NEED HEP NOW!!!)

diamong [38]

Answer:

x=-2.25,y=-2.25

Step-by-step explanation:

The given system is

$4x - y = - 9 \\ 3x - 3y = 0$

We want to solve the system for x and y that makes the system true.

Let us multiply the first equation by 3 while maintaining the second equation:

$12x -3 y = - 27 \\ 3x - 3y = 0$

Subtract the current second equation from the first one.

$12x = - 27$

Divide through by 12:

$x = - \frac{27}{12} = - 2.25$

From the second equation we have:

$3x = 3y$

This implies that:

$x = y = - 2.25$

8 0

4 years ago

a motorist left home at 10 a.m. to travel to a cityof a distance of 260 km he reckoned hecould average 80km/ h at what time woul

kap26 [50]

Answer:

He would get there at 1:15 (I did this in my head, may be wrong)

Step by step solution:

We know the motorist left home at 10. We can divide the 260/80 and we get 3 hrs, we still have 20 km left over, keep on dividing and you get 1:15 p.m.

6 0

3 years ago

Write these numbers as fractions. Simplify the answers. 0.5, 12.3, 0.07, 0.625

motikmotik

0.5 => 5/10 => 1/2

12.3 => 123/10

0.07 => 7/100

0.625 => 625/1000 => 25/40 => 5/8

4 0

3 years ago

Read 2 more answers

How many ounces is in a ton

Alenkasestr [34]

32000 ounces = 1 ton

5 0

4 years ago

Read 2 more answers

At a store, markers are sold in packages of 12 and pens are sold in packages of 8. What is the least amount of markers and pens

liubo4ka [24]

Given:

Markers are sold in packages of 12 and pens are sold in packages of 8.

To find:

Least amount of markers and pens Rick needs to buy to have an equal number of markers and pens

Solution:

To find the least amount of markers and pens, we need to find the LCM of 12 and 8.

Prime factors of 8 and 12 are

$8=2\times 2\times 2$

$12=2\times 2\times 3$

To find the LCM, multiply all factors but the common factors are included only once.

$LCM(8,12)=2\times 2\times 2\times 3$

$LCM(8,12)=24$

Therefore, the least amount of markers and pens Rick needs to buy to have an equal number of markers and pens is 24.

5 0

4 years ago