The position function of an object moving along a straight line is given by s=f(t). The average velocity of an object over the t
ime interval [a,b] is the average rate of change of f over [a,b]; it’s velocity at t=a is the rate of change of f at a. A ball is thrown straight up with an initial velocity of 144ft/sec, so that it’s height (in feet) after t sec is given by s=f(t)= 144t-16t^2.
(A)What is the average velocity of the ball over the following time intervals?
[3,4]= ft/sec
[3,3.5]= ft/sec
[3,3.1]= ft/sec
(B) what is the instantaneous velocity at time t=3? Ft/sec
(C) what is the instantaneous velocity at time t=8? Ft/sec
A) Position at time t = 3 s : <span>s₁ = 144×3 - 16×3² = 288 ft </span> Position at time t = 4 s : <span>s₂ = 144×4 - 16×4² = 320 ft </span> <span>Δs = s₂ - s₁ = 320 - 288 = 32ft </span> <span>Δt = t₂ - t₁ = 4 - 3 = 1 s