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Yuliya22 [10]
3 years ago
10

-2n-h(4rx-6s)-3rx+3s i need help doing this problem

Mathematics
2 answers:
makkiz [27]3 years ago
7 0

<em>- 2n - h(4rx - 6s) - 3rx + 3s =</em>

<em>= - 2n - h×4rx - h×(- 6s) - 3rx + 3s</em>

<em>= - 2n - 4hrx + 6hs - 3rx + 3s</em>

<em> = 2(3hs - 2hrx - 2) - 3(rx - s)</em>

Snezhnost [94]3 years ago
4 0
Ok, first step is to distribute the h to get rid of parenthesis:

-2n - 4hrx + 6hs -3rx +3s

Then you would combine like terms, but there are none! So that's your answer.
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If LW = 5x + 2 and LJ = 11x + 2 in the parallelogram below. Find LW.
WITCHER [35]

Answer:

A. 12

Step-by-step explanation:

Recall: one of the properties of a parallelogram is that the diagonals bisect each other. This means that:

LJ = 2(LW)

11x + 2 = 2(5x + 2)

11x + 2 = 10x + 4

11x + 2 - 2 = 10x + 4 - 2

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Plug in the value of x

LW = 5(2) + 2

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What is the transformation of the logarithmic function from the parent log5 x?
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I need help with this calculus question
Bezzdna [24]

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8 0
3 years ago
Read 2 more answers
Show all work to solve by factoring 3x^2 − x − 2 = 0.
shtirl [24]

Answer:

The solutions are x=1 and x=-2/3

Step-by-step explanation:

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Group terms that contain the same variable, and move the constant to the opposite side of the equation

3x^{2}-x=2

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3(x^{2}-(1/3)x)=2

Complete the square. Remember to balance the equation by adding the same constants to each side

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Rewrite as perfect squares

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square root both sides

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x=(1/6)(+/-)(5/6)

x=(1/6)(+)(5/6)=1

x=(1/6)(-)(5/6)=-2/3

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3 years ago
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