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Ivanshal [37]
4 years ago
13

Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t

he different types of ranges. Give as much information as possible.

Mathematics
1 answer:
NISA [10]4 years ago
5 0

Answer:

Class second have higher score and have greater spread.

Step-by-step explanation:

For first box plot

\text{Minimum value }= 53

Q_1=62

Median=80

Q_3=86

\text{Maximum value }= 89

Range=Maximum-Minimum=89-53=36

IQR=Q_3-Q-1=86-62=24

For second box plot

\text{Minimum value }= 56

Q_1=62

Median=74

Q_3=89

\text{Maximum value }= 96

Range=Maximum-Minimum=96-56=40

IQR=Q_3-Q-1=89-62=27

First class has greater minimum value, it means first class has lower grades.

First quartile of both classes are same, it means equal number students in both classes have less than 62 marks.

First class has greater median.

second class has greater third quartile.

Second class has greater Maximum value.  It means second class have higher score than first class.

Second class has greater range. It means the data of second class has greater spread.

Second class has greater inter quartile range.  It means the data of second class has greater spread.

Therefore, the class second have higher score and have greater spread.

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3 years ago
Solve the system of equations by graphing: 2x + 3y = 2 6x + 18y = 9
cluponka [151]
The answer is  A: x=1/2 , y= 1/3

Solve the following system:
{2 x + 3 y = 2 | (equation 1)
{6 x + 18 y = 9 | (equation 2)

Swap equation 1 with equation 2:
{6 x + 18 y = 9 | (equation 1)
{2 x + 3 y = 2 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:
{6 x + 18 y = 9 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Divide equation 1 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Multiply equation 2 by -1:
{2 x + 6 y = 3 | (equation 1)
{0 x+3 y = 1 | (equation 2)

Divide equation 2 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x+y = 1/3 | (equation 2)

Subtract 6 × (equation 2) from equation 1:
{2 x+0 y = 1 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Divide equation 1 by 2:
{x+0 y = 1/2 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Collect results:
Answer:  {x = 1/2, y = 1/3

7 0
3 years ago
Which is the graph of x – y = 1?
Jet001 [13]

Answer:

its the second graph

Step-by-step explanation:

you could use this website to find out graph

desmos calculator

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olchik [2.2K]
Check the picture below.

thus is at 0 = -16t² + 96t +640,

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\\\\\\
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\begin{cases}
\boxed{10}\\
-4
\end{cases}

well, clearly it can't be a negative value for the elapsed seconds, so it can't be -4.

5 0
3 years ago
I need help for Part A and B
Tamiku [17]

Step-by-step explanation:

A

The probability of wining is 1/4 so it's 25%. so if you win you either win one of 2 object, so we have to divide the chance of wining by the number of object, so (25%)/2

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