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3 years ago

Charlie is trying to hold on to his toy fire truck.

1 answer:

8 0

His brother Noah is pulling with a force of 8 N on a bearing of 023° and his brother Jude with a force of 5 N on a bearing of 155°.

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Solve the inequality 1/3(x-6)>2

ludmilkaskok [199]

Answer:

x>12

Step-by-step explanation:

1/3(x-6)>2

distribute 1/3

1/3x-2>2

add 2 to both sides

1/3x>4

multiply both sides by 3

x>12

3 0

3 years ago

one room length 12.8 and breadth equals to 850 CM inside that room there is a bad length is 300 cm and breadth is 400 cm find th

9966 [12]

Answer:

$Area = 968000cm^2$

Step-by-step explanation:

To be able to answer this question properly. I'll assume the length of the room is in meters.

So for the room, we have:

$Length = 12.8m$

$Breadth = 850cm$

For the bed, we have:

$Length = 300cm$

$Breadth = 400cm$

First, we calculate the surface area of the room.

$A_1 = 12.8m * 850cm$

Convert all units to cm

$A_1= 12.8*100cm * 850cm$

$A_1= 1 088 000 cm^2$

Next, we calculate the area of the bed

$A_2 = 300cm * 400cm$

$A_2 = 120000cm^2$

The area of the space left is the difference between A1 and A2

$Area = A_1 - A_2$

$Area = 1088000cm^2 - 120000cm^2$

$Area = 968000cm^2$

5 0

3 years ago

Will give brainliest if helpful!!!!! :)

dolphi86 [110]

Answer:

I hope this help

Step-by-step explanation:

I hope this help

7 0

3 years ago

Read 2 more answers

Given m

kenny6666 [7]

Answer:

Step-by-step explanation:

Given, 

m || n

So,

35° = y° [Alternate interior angles]

And,

y° + x° = 180° [Since linear pair]

=> x + 35 = 180

=> x = 180 - 35

=> x = 145°

Hence, 

x = 145°, y = 35°

6 0

3 years ago

Read 2 more answers

PLEASE HELP!!!!!

Sidana [21]

Answer:

Part a) The distance on a map between Joseph's house and the airport is 2.53 inches

Part b) The distance on a map between the airport and the restaurant is 1.68 inches and the total distance on a map between Joseph's house and the restaurant is 4.21 inches

Step-by-step explanation:

Part a) The actual distance between Joseph's house and the airport is 24 miles. How far apart are Joseph's house and the airport on the map?

we know that

The scale of a map is 1 inch : 9.5 miles

using proportion

Find the distance on a map if the actual distance between Joseph's house and the airport is 24 miles

Let

x-----> the distance on a map

1/9.5=x/24

x=24/9.5=2.53 inches

Part b) Joseph traveled from his house to the airport. He then traveled another 16 miles past the airport to a restaurant. How many inches on the map represent this distance?

we know that

The scale of a map is 1 inch : 9.5 miles

using proportion

Find the distance on a map if the actual distance between airport to the restaurant is 16 miles

Let

x-----> the distance on a map

1/9.5=x/16

x=16/9.5=1.68 inches

The total distance on a map between Joseph's house and the restaurant is equal to

2.53 inches+1.68 inches=4.21 inches

3 0

3 years ago