Find the slope of the line that passes through the points (0,7) and (-4,7)

A newspaper stand sold 1000 copies of the city newspaper for $1600. Write and solve an equation to find the price of one copy.

Goshia [24]

Simple. just do this:
1000x=1600
x=1600÷1000
x=1.6

each newspaper is $1.60

8 0

4 years ago

Read 2 more answers

Can someone help me pls it due In the next two hrs

Lubov Fominskaja [6]

Answer:

1. More magnets are longer than 2 1/2

2. 10 magnets measure in whole numbers and 5 magnets between 2 whole numbers

3. Because the shortest magnet is 1 inch and the longest magnet is 4 inches.

Step-by-step explanation:

1. There are 7 magnets that are longer than 7 1/2 and only 6 magnets that are shorter than 2 1/2. (The 2 magnets that are exactly 2 1/2 are neither longer nor shorter therefore they do not apply to the question.)

5 0

3 years ago

The charity gala costs $5.17 for every attendee. How many attendees can there be, at most, if the budget for the charity gala is

Elodia [21]

Answer:

15 people are able to be at the charity gala because 77:55 divided by 5:17.

3 0

3 years ago

A tire manufacturer is considering a newly designed tread pattern for its all-weather tires. Tests have indicated that these tir

Nataly_w [17]

Answer:

With outlier (102)

$t=\frac{126.2-125}{\frac{9.138}{\sqrt{10}}}=0.415$

$p_v =P(t_{9}>0.415)=0.344$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 125 feet at 5% of significance.

Without outlier (102)

$t=\frac{128.89-125}{\frac{3.551}{\sqrt{9}}}=3.285$

$p_v =P(t_{8}>3.285)=0.0056$

And we conclude that we reject the null hypothesis since $p_v$ . So the final conclusion would be not use the method since the value of 102 observed can be a potential outlier, removing this value we see that we reject the null hypothesis and we have a significant result that the true mean is higher than 125.

Step-by-step explanation:

Previous concepts and data given

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data: 129, 128, 130, 132, 135, 123, 102, 125, 128, 130

We can calculate the mean with the following formulas:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=126.2$ represent the sample mean

$s=9.138$ represent the sample standard deviation

n=10 represent the sample selected

$\alpha$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is significantly higher than 125, the system of hypothesis would be:

Null hypothesis: $\mu \leq 125$

Alternative hypothesis: $\mu > 125$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{126.2-125}{\frac{9.138}{\sqrt{10}}}=0.415$

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=10-1= 9$

Then since is a right tailed sided test the p value would be:

$p_v =P(t_{9}>0.415)=0.344$

Conclusion

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 125 feet at 5% of significance.

Using all the data we see that we don;t have enough info to conclude that the true mean is higher than 125, but if we see careful 9 of the 10 values are over the limit of 125 feet. And if we repeat the procedure with the outlier of 102. We got this:

$\bar X=128.89$ represent the sample mean

$s=3.551$ represent the sample standard deviation

$t=\frac{128.89-125}{\frac{3.551}{\sqrt{9}}}=3.285$

First we need to calculate the degrees of freedom given by:

$df=n-1=9-1= 8$

Then since is a right tailed sided test the p value would be:

$p_v =P(t_{8}>3.285)=0.0056$

And we conclude that we reject the null hypothesis since $p_v$ . So the final conclusion would be not use the method since the value of 102 observed can be a potential outlier removing this value we see that we reject the null hypothesis and we have a significant result that the true mean is higher than 125.

8 0

3 years ago

A line passes through the points (2,-2) and (-6,2). The point (a.-4) is also on the line. What is the value of a?

Zigmanuir [339]

Answer:

Step-by-step explanation:

Hey there) The formula of your line is:

$-2=2k+b\\2=-6k+b\\=>4=-8k\\k=-0.5\\=> b=-2+1=-1\\=>y=-\dfrac{1}{2}x-1\\$

If point has y=-4, then:

$-4=-\dfrac{1}{2}a-1\\4=\dfrac{1}{2}a+1\\a=6$

Hope this helps) Have a nice day/night :)

8 0

4 years ago

Find the slope of the line that passes through the points (0,7) and (-4,7) ​

Find the slope of the line that passes through the points (0,7) and (-4,7)