It is in the air 5.625 seconds.

Using the quadratic formula,

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}
\\
\\=\frac{-90\pm \sqrt{90^2-4(-16)(0)}}{2(-16)}
\\
\\=\frac{-90\pm \sqrt{8100-0}}{-32}
\\
\\=\frac{-90\pm \sqrt{8100}}{-32}=\frac{-90\pm90}{-32}
\\
\\=\frac{-90+90}{-32}\text{ or }\frac{-90-90}{-32}=\frac{0}{32}\text{ or }\frac{-180}{-32}
\\
\\=0\text{ or }5.625$

0 is when the ball is first launched, 5.625 is when it hits the ground again.

4 0

3 years ago

Which equation has no solution?

prohojiy [21]

Answer:

Step-by-step explanation:

C.

5/8x + 25 = 3/8x + 15 + 1/4x
5/8x + 10 = 3/8x + 2/8x
5/8x + 10 = 5/8x
10 = 0

3 0

3 years ago

Please answer the attached question.

Nikitich [7]

Answer : fx + fh - f(x) / h

6 0

3 years ago