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aivan3 [116]
3 years ago
6

Write a two column proof for the reflexive property of Angel congruence

Mathematics
1 answer:
olasank [31]3 years ago
6 0
If you can separate the figures and the segment, or angle in question, is the same, the reflexive property of congruence can be used in the proof. ... Separating the two triangles, you can see Angle Z is the same angle for each triangle. Since they are the same angle, the angle is congruent to itself.
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A phone company offers two monthly plans. Plan A costs $18 plus an additional $0.11 for each minute of calls. Plan B costs $8 pl
Anastasy [175]

Answer:

you did not tell us what to calculate in the question

5 0
4 years ago
When Helen jogs, every $20$ minutes she checks the total distance she traversed. One day, the first time she checked, Helen had
german
The difference between speeds, during the first 20 minutes and last 20 minutes, would be 4.3 miles. The key word here is difference which automatically tells us to subtract. In this case you would subtract 6.8 miles, the last 20 minutes, by 2.5 miles, the first 20 minutes. In the end, getting 4.3 miles. Hope this helps! :)
3 0
4 years ago
What are the coordinates of point A?​
Ratling [72]

Answer:

  (d)  (7, -5)

Step-by-step explanation:

The x-coordinate is listed first in an ordered pair. It is found on the horizontal scale. The point is on the grid line halfway between 6 and 8, so is presumed to have an x-coordinate of 7.

The y-coordinate is listed second in an ordered pair. It is found on the vertical scale. The point is on the grid line halfway between -4 and -6, so is presumed to have a y-coordinate of -5.

The coordinates of point A are (x, y) = (7, -5).

__

<em>Additional comment</em>

As in the case here, you will often run across graphs that don't have markings on every grid line You are expected to be able to figure out the value of a grid line based on the spacing of the marked lines.

It is a good idea to get familiar with reading coordinates of a point on a graph, as you will be doing it a lot.

4 0
2 years ago
In 2002, the mean age of an inmate on death row was 40.7 years with a standard deviation of 9.6 years according to the U.S. Depa
marissa [1.9K]

Answer:

The <em>95% confidence interval</em> for the current mean age of death-row inmates is between 42.23 years and 35.57 years.

Step-by-step explanation:

The <em>confidence interval</em> of the mean is given by the next formula:

\\ \overline{x} \pm z_{1-\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}} [1]

We already know (according to the U.S. Department of Justice):

  • The (population) standard deviation for this case (mean age of an inmate on death row) has a standard deviation of 9.6 years (\\ \sigma = 9.6years).
  • The number of observations for the sample taken is \\ n = 32.
  • The sample mean, \\ \overline{x} = 38.9 years.

For \\ z_{1-\frac{\alpha}{2}}, we have that \\ \alpha = 0.05. That is, the <em>level of significance</em> \\ \alpha is 1 - 0.95 = 0.05. In this case, then, we have that the <em>z-score</em> corresponding to this case is:

\\ z_{1-\frac{\alpha}{2}} = z_{1-\frac{0.05}{2}} = z_{1-0.025} = z_{0.975}

Consulting a cumulative <em>standard normal table</em>, available on the Internet or in Statistics books, to find the z-score associated to the probability of, \\ P(z, we have that \\ z = 1.96.

Notice that we supposed that the sample is from a population that follows a <em>normal distribution</em>. However, we also have a value for n > 30, and we already know that for this result the sampling distribution for the sample means follows, approximately, a normal distribution with mean, \\ \mu, and standard deviation, \\ \sigma_{\overline{x}} = \frac{\sigma}{\sqrt{n}}.

Having all this information, we can proceed to answer the question.

Constructing the 95% confidence interval for the current mean age of death-row inmates

To construct the 95% confidence interval, we already know that this interval is given by [1]:

\\ \overline{x} \pm z_{1-\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

That is, we have:

\\ \overline{x} = 38.9 years.

\\ z_{1-\frac{\alpha}{2}} = 1.96

\\ \sigma = 9.6 years.

\\ n = 32

Then

\\ 38.9 \pm 1.96*\frac{9.6}{\sqrt{32}}

\\ 38.9 \pm 1.96*\frac{9.6}{5.656854}

\\ 38.9 \pm 1.96*1.697056

\\ 38.9 \pm 3.326229

Therefore, the Upper and Lower limits of the interval are:

Upper limit:

\\ 38.9 + 3.326229

\\ 42.226229 \approx 42.23 years.

Lower limit:

\\ 38.9 - 3.326229

\\ 35.573771 \approx 35.57 years.

In sum, the 95% confidence interval for the current mean age of death-row inmates is between 42.23 years and 35.57 years.

Notice that the "mean age of an inmate on death row was 40.7 years in 2002", and this value is between the limits of the 95% confidence interval obtained. So, according to the random sample under study, it seems that this mean age has not changed.

7 0
4 years ago
What is the value of log2 81?
mestny [16]

6.33985000288

i used a calculator

╦────────────────────────────╦

│Hope this helped  _____________________│    

│~Derelis ____________________________ │

╨___________________________________╨                  

7 0
3 years ago
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