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2 years ago

Which is a solution of the equation? 2x - y = 5 O 7 O (3,-1) O (2,-1) O (1,2)

Mathematics

1 answer:

Tju [1.3M]2 years ago

6 0

Answer:

I'm not sure what the answer is, but try Photo math. it helps me so much with my equations, and it'll even tell you the steps to get the answer.

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Is 15b+4=25.6 equivalent to 0.6+15b+4=25.6

pychu [463]

No because
15b + 4 = 25.6
15b = 21.6
b = 1.44

0.6+15b+4 = 25.6
4.6 + 15b = 25.6
15b = 21
b = 1.4

The answers are not the same therefore they are not equivalent.

3 0

3 years ago

NEED HELP WILL MARK BRANLYEST

BlackZzzverrR [31]

Answer:

The first of the rows should go with each other. The 36/125^3 does with the second one. The 6/125^3 goes to the third one. The last row goes with 8/125 cm^3

Step-by-step explanation:

6 0

2 years ago

Which graph represents the solution set of the compound inequality below? x + 3 < (4x – 12) < 20

nordsb [41]

x + 3 < 4x - 12 or 4x - 12 < 20

-x -x +12 +12

3 < 3x - 12 or 4x < 32

+12 +12 ÷4 ÷4

15 < 3x or x < 8

÷3 ÷3

5 < x

5 < x < 8

Graph: 5 o---------------o 8

6 0

3 years ago

Read 2 more answers

Suppose you decide to put $12,500 in an account earning 9% interest compounded quarterly. How much interest would you earn after

Vesnalui [34]

Step-by-step explanation:

you add 9% to a number by multiplying that number by 1.09.

because adding 9% gives us in the end 109% of the original amount.

anyway, the formula for quarterly compounded interest is

Cq = P [ (1+r)^(4*n) – 1 ]

P is the starting principal amount

r is the interest rate per quarter (= interest rate / 4)

n would be the number of years (= 1 in our case).

so, the interest after 1 year is

12500((1 + 0.09/4)⁴ - 1) = 12500(1.0225⁴ - 1) =

= 12500 × 0.093083319 = $1,163.541485 ≈ $1,163.54

8 0

1 year ago

which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

6 0

3 years ago