When graphing an ordered pair, what is the first number and what does it tell you to do?

2 answers:

7 0

The answer is D. In an ordered pair, the x-value, which tells you to move left or right, comes first, followed by the y-value, which tells you to move up or down.

jonny [76]4 years ago

6 0

D. the answer is D. (X,Y)

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A local bakery buys their flour in bulk. The relationship between the cost of the flour and its weight is shown in the graph bel

Nataly [62]

The relationship shown for the flour and the cost is that of a direct variation because the graph is a straight line, noting that the increase of one variable causes also the increase to the value of the other. The point (1, 0.75) means that every pound of flour costs 0.75 dollar. From the graph given, the bakery will have to pay approximately $30 for 40 pounds of flour.

8 0

4 years ago

Two circles with different radii have chords AB and CD, such that AB is congruent to CD. Are the arcs intersected by these chord

emmainna [20.7K]

The arcs intersected by these chords are not congruent.

Given that two circles with different radii have chords AB and CD, such that AB is congruent to CD.

Let r₁ and r₂ be the radii of two different circles with centers O and O' respectively.

Assuming that the each of the ∠АОВ and ∠CO'D is less than or equal to π.

Then, we have isosceles triangle AOB and CO'D such that,

AO = OB = r₁,

CO' = O'D = r₂,

Let us assume that r₁< r₂;

We can see that arc(AB) intersected by AB is greater than arc(CD), intersected by the chord CD;

arc(AB) > arc(CD) .......(1)

Indeed,

arc(AB) = r₁ angle (AOB)

arc(CD) = r₂ angle (CO'D)

So, we have to prove that ;

∠AOB >∠CO'D ......(2)

Since each angle is less than or equal to π, and so

∠AOB/2 and ∠CO'D/2 is less than or equal to π

it suffices to show that :

tan(AOB/2) >tan(CO'D/2) ......(3)

From triangle AOB :

tan(AOB/2) = AB/(2*r₁)

tan(CO'D/2) = CD/(2*r₂)

Since AB = CD and r₁ < r₂ (As obtained from the result of (3) ), therefore, arc(AB) > arc(CD).

Hence, for two circles with different radii have chords AB and CD, such that AB is congruent to CD but the arcs intersected by these chords are not congruent.

Learn more about congruent from here brainly.com/question/1675117

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